374u
187u
C₁₄H₂₂N₄O₈
Explanation:
To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.
The empirical weight is determined by using the simplest ratio of the elements involved in the compound;
Molecular weight of C₁₄H₂₂N₄O₈;
atomic mass of C = 12g/mol
H = 1g/mol
N = 14g/mol
O = 16g/mol
Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)
= 168 + 22 + 56 + 128
= 374u
Empirical weight:
Empirical formula:
C₁₄ H₂₂ N₄ O₈
14 : 22 : 4 : 8
divide by 2:
7 : 11 : 2 : 4
empirical formula C₇H₁₁N₂O₄
empirical weight = 
= 
= 187u
The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈
learn more:
Molecular mass brainly.com/question/5546238
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Correct compound is [Co(H2O)6]^+3
The oxidation state of Co is +3
[Co(H2O)6]^+3
Let
Co be x
H2O = 0
x + (0)6 = 3
x = 3
What is oxidation state?
The oxidation state, commonly known as the oxidation number, is the potential charge that an atom would have if all of its bonds to other atoms were fully ionic. It describes the degree of atom oxidation within a chemical compound.The oxidation state may be positive, negative, or zero in theory.
The oxidation number, sometimes referred to as the oxidation state, is the total number of electrons that an atom gains or loses while uniting with another atom to form a chemical bond.
To learn more about oxidation state click the given link
brainly.com/question/8990767
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Answer: the exciation of molecules is brount by absorption of energy in spectroscpy
Explanation:
Answer:
3.82 × 10 ^-23 g
Explanation:
6.02 x 10^23atoms = 1 mole of sodium
1 atom = 1/(6.02 x 10^23) mole
mass = mole × molar mass
= 1/(6.02 x 10^23) × 23
= 3.82 × 10 ^-23 g
