9514 1404 393
Answer:
12 liters
Step-by-step explanation:
The kerosene usage is assumed to be jointly proportional to the number of stoves and the number of hours. That is ...
v = k·s·h . . . . . for s stoves running h hours
Then the value of k is ...
k = v/(sh) = (16 L)/(12·14) = 2/21 . . . . liters per stove-hour
Then the volume of kerosene required for 7 stoves and 18 hours is ...
v = (2/21)·s·h
v = (2/21)(7)(18) = 12 . . . liters
Answer:
m=-3/7
Step-by-step explanation:
(-4,2), (-3,5)
x1 y1 x2 y2
m=<u>y2-y1</u>
x2-x1
m=<u>5-2</u>
-3-4
m=<u>3</u>
-7
m=-3/7
The answer would be, it was reduced by 35%
Answer:
I am willing to help, just send your problems in the comments!
Step-by-step explanation:
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