Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;
then;
or
miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles
Your triangle has acute angles X and Y, and right angle Z.
For an acute angle A in a right triangle:
The sine is the ratio of the opposite leg to the hypotenuse.
sin A = opp/hyp
The cosine is the ratio of the adjacent leg to the hypotenuse.
cos A = adj/opp
The hypotenuse of a right triangle is the side opposite the right angle. It is the longest side of a right triangle. There is only one hypotenuse in a triangle, so there is no confusion with the hypotenuse.
The two sides that form the right angle are called the legs. Each leg is opposite an acute angle. The legs may or may not be congruent to each other, but each leg is always shorter than the hypotenuse. Since there are two legs, we need to be able to distinguish them. If you take an acute angle as your angle of interest, the leg that is part of the angle is called the adjacent leg. The other leg is the opposite leg. Adjacent leg and opposite leg are relative terms. They depend on the acute angle you are considering.
For your triangle, if you look at angle X, then the adjacent leg is side XZ. The opposite leg for angle X is side YZ.
Using the ratios mentioned above for sine and cosine, you get:
sin X = opp/hyp = sqrt(119)/12
cos X = adj/hyp = 5/12
Answer:
53
Step-by-step explanation:
Let x be the number of children tickets sold and y be the number of adult tickets sold. Then
x+y=128.
The cost of x children tickets is $5.10x and the cost of y adult tickets is $9.70y, so
5.10x+9.70y =896.60.
From the first equation,
x=128-y,
then
53 adult tickets were sold.
Answer:
Step-by-step explanation:
To solve this, we are using the average rate of change formula:
where
is the average rate of change
is the first point
is the second point
is the function evaluated at the first point
is the function evaluated at the second point
We want to know the average rate of change of the function 
form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words, 
and 
.
Replacing values
We can conclude that the average rate of change of the exponential equation form x = -3 to x = 0 is
6,372 I used a calculator, I hope this helps
