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harkovskaia [24]
3 years ago
15

What are two numbers that have a product of 12 and a sum of 5

Mathematics
1 answer:
pashok25 [27]3 years ago
6 0

Answer:

there are no two numbers that have a product of 12 and a sum of 5 make sure that the question is correct

yo can find two numbers that have a product of 12 and a sum of 7 the answer is 3 and 4 .

Step-by-step explanation:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Can u help me with these math problems
Vlada [557]

Answer:

Q3: A

Q4: 9x² + (-x) + (-3)

Step-by-step explanation:

Q3: C (63) => x = 63. => C(x) = 36 x 63

Q4: f(x) + g(x) = 7x² - 5x + 3 + 2x² + 4x - 6 = (7x² + 2x²) + (-5x + 4x) + (3 - 6) = 9x² + (-x) + (-3)

8 0
3 years ago
Which equation is equivalent to the equation 6x + 9=12
quester [9]

Answer:

the answer is 1/2

Step-by-step explanation:

i solved it

6 0
3 years ago
Work out the volume of the shape​
pashok25 [27]

Answer:

\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}

Step-by-step explanation:

We have the cone and the half-sphere.

The formula of a volume of a cone:

V_c=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have r = 7cm and H = (22-7)cm=15cm. Substitute:

V_c=\dfrac{1}{3}\pi(7^2)(15)=\dfrac{1}{3}\pi(49)(15)=\dfrac{735\pi}{3}\ cm^3

The formula of a volume of a sphere:

V_s=\dfrac{4}{3}\pi R^3

R - radius

Therefore the formula of a volume of a half-sphere:

V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3

We have R = 7cm. Substitute:

V_{hs}=\dfrac{2}{3}\pi(7^3)=\dfrac{2}{3}\pi(343)=\dfrac{686\pi}{3}\ cm^3

The volume of the given shape:

V=V_c+V_{hs}

Substitute:

V=\dfrac{735\pi}{3}+\dfrac{686\pi}{3}=\dfrac{1,421\pi}{3}\ cm^3

7 0
3 years ago
Which expression is equivalent to 18s+9t+36
tatuchka [14]

18(s+t/2+2)

18(s+t/2+2)

8 0
3 years ago
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