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3 years ago

9

15. The price of a ticket for your office Christmas party is $17.75. So far you've sold 28 tickets. How much money should you ha

ve? A. $330 B. $495 C. $497 D. $427

1 answer:

Marina CMI [18]3 years ago

5 0

17.75 x 28 = 497
you answer is C

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Consider the equation 3a+0.1n=123. If we solve this equation for n, which equation would result? A. 0.1n=123-3a B. N=123-3a-0.1

neonofarm [45]

Answer:

n = (123 - 3a) / 0.1

Step-by-step explanation:

Given:

3a + 0.1n = 123

Solve for n

3a + 0.1n = 123

Subtract 3a from both sides

3a + 0.1n - 3a = 123 - 3a

0.1n = 123 - 3a

Divide both sides by 0.1

n = (123 - 3a) / 0.1

The resulting equation if 3a + 0.1n = 123 is solved for n is n = (123 - 3a) / 0.1

4 0

3 years ago

1 1/4 as a improper fraction

ludmilkaskok [199]

That would be
5/4
.
Explanation:
This answer is valid because, when you multiply
4
×
1
, you get
4
. Then add one and keep the denominator, you will get
5
4
.
1
1
4
=
1
×
4
+
1
4
=
5
4
When you simplify
5
4
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1
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Have a great day!

8 0

3 years ago

Read 2 more answers

The buyer for a chain of stores purchased lawn ornaments in bulk, paying $23 each. The stores will sell each lawn ornament for $

Naya [18.7K]

Answer:

The markup percentage is 61.2

Step-by-step explanation:

Given as :

The cost price of each ornaments = $23

The sell price of each ornament = $37.08

Let The markup percentage = x

<u>Now, According to question</u>

Markup percentage = $\dfrac{s.p - c.p}{c.p}$ × 100

Or, x% = $\dfrac{37.08 - 23}{23}$

Or, x% = $\dfrac{14.08}{23}$

Or, x% = 0.612

∴ x = 0.612 × 100

I.e x = 61.2

So, The The markup percentage = x = 61.2

Hence, The markup percentage is 61.2 Answer

8 0

3 years ago

PLEASE HELP<br> log (5x – 10) = log (6 – 5x)

Bond [772]

Answer: look at the picture

Step-by-step explanation: Hope this help :D, Can I have a Brainliest I really needed it please

7 0

3 years ago

Find the solution of the system of equations.<br> 10x+10y=40 <br> 5x+3y=8

ddd [48]

Answer:

x = -2 & y = 6

Step-by-step explanation:

$10x+10y=40$

$10x+10y+ -10y=40+-10y$

$10x=-10y+40$

$\frac{10x}{10} =\frac{-10y+40}{10}$

$x=-y+4$

$5x+3y=8$

$5(-y+4)+3y=8$

$-2y+20=8$

$-2y+20+-20=8+-20$

$-2y=-12$

$\div2$

$y=6$

$x=-y+4$

$x=-6+4$

$x=-2$

Hope this helps.

7 0

2 years ago