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Harlamova29_29 [7]
3 years ago
13

If I cut 2/3 of a pie and put the big piece on my plate. Then eat 1/4 of the piece. What fraction of the original pie did I eat.

Mathematics
2 answers:
Sphinxa [80]3 years ago
7 0

2/3 = 8/12 (GCD of 3 and 4 is 12. 3 * 4 = 12, 2 * 4 = 8)

1/4 = 3/12 (4 * 3 = 12, 1 * 3 = 3)

8/12 - 3/12 = 5/12

You ate 5/12 of the pie

I'm not sure if this really helps anyone that reads it, but that's how I was taught. You can correct me if I'm wrong.

P.S. I know I'm late for it

Hunter-Best [27]3 years ago
6 0
If you took \frac{2}{3} of a pie then only ate \frac{1}{4} of that slice, you ate \frac{1}{4} of \frac{2}{3}.

\frac{2}{3} * \frac{1}{4} = \frac{2}{12}

Simplify.

\frac{2}{12} = \frac{1}{6}

So, you ate 1/6 of the pie.
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SECTION B
lapo4ka [179]

Answer: The median value of data set B is -5.5, which is less than the median value of 3.1 in dataset A.

Step-by-step explanation:

Order the dataset from least to greatest:

-38 → -13 → -9 → -2 → 14 → 28

Then find the values that lies in the middle:

-38 → -13 → <u>-9 → -2</u> → 14 → 28

Since there are 2 values, find the average of those 2 values:

\frac{-9+(-2)}{2} =\frac{-11}{2} =-5.5

The median value = -5.5.

The median value of data set B is -5.5, which is less than the median value of  3.1 in dataset A.

3 0
3 years ago
There are 30 marbles in a bag. 24 of them are blue. What percentage of the marbles are blue?
lorasvet [3.4K]

Answer:

80%

Step-by-step explanation:

24/30 = x/100

100/30= 3 1/3

24 x 3 1/3= 80

3 0
3 years ago
Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p
zubka84 [21]

Answer:  The required answers are

(a) 0.25,    (b) 0.62,    (c) 6.

Step-by-step explanation:  Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.

(a) The probability of getting 5 heads is given by

P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.

(b) The probability of getting 5 or more than 5 heads is

P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

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3 years ago
A football team gained 7 yards in one play. What integer represents the amount of yards the football team gained​?
Goshia [24]

Answer:

y + 7 = x

Step-by-step explanation:

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How can the following fraction 33/77 be in simplest form??
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3/7 top and bottom are divisible by 12
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