The volume of a cube is V=s^3, so s=V^(1/3).
The area of a cube is A=6s^2, using s found above we have:
A=6(V^(2/3))
Let V and S be the volume and area of the larger and v and s be the volume and area of the smaller cube.
A:a
6(V^(2/3)):6(v^(2/3))
V^(2/3):v^(2/3), we are given that V=216 and v=64 so
216^(2/3):64^(2/3)
36:16
9:4
Answer:
Using the combination formula:
Number of combination of r object chosen from the total object i.e n is given by:

As per the statement:
4 candy bars be chosen from a store that sells 30 candy bars
Number of candy bars chosen from a store that sells 30 candy bars(r)= 4
and
Total candy bars(n) = 30
then substitute in the given formula we have;

⇒
⇒
Simplify:
⇒
therefore, 27,405 ways can 4 candy bars be chosen from a store that sells 30 candy bars
33.51 X 85% (0.85) = 28.48
Answer:
Domain:- All real numbers
Range:-[3,infinite)
Step-by-step explanation:
In the function there's no value of x for which it is not defined thus domain is R.
Now a modulus will have always it's minimum value 0 thus minimum value of function is 0+3=3. And Max value of a modulus is infinite so infinite+3=infinite.