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vladimir1956 [14]
4 years ago
11

Can somebody solve this for me?

Mathematics
1 answer:
belka [17]4 years ago
7 0
Student 1 estimated 4.4 pounds away from the actual weight of 15.6 pounds.

               His error was  ( 4.4/15.6 )  =  0.282  =  28.2 % .

Student 2 estimated 0.7 ounces away from the actual weight of 14.3 ounces.

               Her error was  ( 0.7/14.3 )  =  0.049  =  4.9 %

Student 3 estimated 2.7 pounds away from the actual weight of 12.7 pounds.

               Her error was  ( 2.7/12.7 )  =  0.212  =  21.2 %

Student 4 estimated 3.6 ounces away from the actual weight of 21.4 ounces.

                His error was  (3.6/21.4 )  =  0.168  =  16.8 % 


Student 1, with an error of a whopping 28.2%, had the largest error.

Student 2, with an error of only 4.9%, had the smallest error.

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Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
ser-zykov [4K]

Answer:

f(x) = x^3 - 2x^2 - x + 2

Step-by-step explanation:

since the zeroes are 1,-1, and 2. we can write the function like

f(x) = (x-1)(x+1)(x-2)

f(x) = (x^2-1)(x-2)

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4 0
3 years ago
Round to 2 decimal places *
EleoNora [17]

Answer: The circumference of the dome is therefore 149.15 feet or 47.5π feet

Step-by-step explanation:

A scale is basically referred to as the ratio of the dimensions of an object as represented in a draft to the real or true dimensions of the object being drafted.

The figure(s) on the left of the ratio sign represents the size and dimensions of the model with respect to the actual size or dimensions of the object. On the other hand, the figure on the right hand size represents the actual dimensions and size of the real object.

So, if an object is being drawn with the ratio, 1cm : 5cm it means that the size of the object is being reduced because every 5cm of the actual object will always be represented by 1cm in the drawing. If the object is being drawn with a scale of 5cm : 1cm then the actual size of the object will be increased in the drawing. That is, for every 1cm in the actual dimensions of the object, there will be a 5cm representation in the drawing.

Now, the architect draws with a scale of 0.25 inches : 1 foot. If the diameter of the hemispherical dome is 23.75 inches in the scale model, then the actual diameter of the dome is:

0.25 inches ------- 1 foot

23.75 inches ------- ? feet

= 23.75/0.25 × 1

= 95 feet

Therefore, the actual diameter of the dome is 95 feet. We are now required to find the circumference of this dome.

The dome is a hemisphere which literally means half of a sphere. So, if the formula for finding the circumference of a sphere is πd, that of a hemisphere will then be πd/2. Since the diameter is already known to be 95 feet, the circumference of the hemisphere =

(π × 95)/2

=47.5π feet

Or

If π = 3.14, then the circumference = (3.14 × 95)/2 = 149.15 feet

The circumference of the dome is 149.15 feet or 47.5π feet

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SOLVE BY SUBSTITUTION OR ELIMINATION<br> 7y=9x+20, 33= -12y-7x
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Point Form:

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Step-by-step explanation:

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