All categories

3 years ago

Jylene and her brother had a total of $35.19 to buy school supplies. Jylene's school supplies cost

Mathematics

1 answer:

cricket20 [7]3 years ago

5 0

Answer:

13.31

Step-by-step explanation:

First do 35.19-12.78=22.41

I assume slightly more than $9 is .1

then subtract 22.41-9.1=13.31

You might be interested in

Can I have help with these? Picture attached.

8_murik_8 [283]

Answer:

5. mCD is 27.8° | 7. mAFC 52.3° |

Step-by-step explanation:

8 0

3 years ago

The perimeter of a rectangular

cupoosta [38]

Answer:

5 ft

Step-by-step explanation:

Since we have a rectangle, we know for sure that perimeter = double the width and double the height. Algebraically, that looks like:

P = 2W + 2H

Let's sub in the given values, P and W:

18 = 2(4) + 2H

Now, let's solve for the height, H:

18 = 8 + 2H

10 = 2H

10/2 = H

I hope this helps!

7 0

3 years ago

Can someone help me ASAP

ryzh [129]

Answer:

36 ft.

Step-by-step explanation:

Use the Pythagoras Theorem.

h^2 = 10^2 + 24^2

h^2 = 676

h = √676

h = 26 ft.

Original height = 10+26 = 36 ft.

5 0

3 years ago

Read 2 more answers

Can someone please me?

juin [17]

Answer:

Its B. "x" is all real numbers. Happens in any case that the line is horizontal. Hope this helps!

6 0

4 years ago

(1 point) a tank contains 1060 l of pure water. a solution that contains 0.06 kg of sugar per liter enters the tank at the rate

kirill115 [55]

(a) There is 0 kg of sugar in the tank at the beginning since it contains pure water at the start. The sugar only comes from the solution.

(b)

$S' = f(t,S) = \left(0.06 \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) - \left(\dfrac{S}{1060} \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) \ \Rightarrow \\ \\ S' = 0.54 \text{ kg}/\text{min} - \dfrac{9S}{1060}$

So yes, you enter S' = 0.54 - (9S/1060)

(c)

$\displaystyle\frac{dS}{dt} = 0.54 - \frac{9S}{1060} \ \Rightarrow\ \frac{dS}{dt} = \frac{572.4 - 9S}{1060}\ \Rightarrow\ \dfrac{dS}{572.4 - 9S} = \frac{1}{1060} dt\ \Rightarrow \\ \\
\int \dfrac{dS}{572.4 - 9S} = \int \frac{1}{1060} dt\ \Rightarrow\textstyle\ -\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t + C \\ \\
S(0) = 0 \ \Rightarrow\ -\frac{1}{9}\ln|572.4 - 0| = \frac{1}{1060}(0) + C\ \Rightarrow\ C = -\frac{1}{9} \ln 572.4$

$-\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t -\frac{1}{9} \ln 572.4\ \Rightarrow \\ \\
\ln|572.4 - 9S| = \ln 572.4 - \frac{9}{1060}t \ \Rightarrow \\ \\
|572.4 - 9S| = e^{\ln 572.4 - 9t/1060}\ \Rightarrow \\ \\
572.4 - 9S= \pm 572.4 e^{-9t/1060}\ \Rightarrow \\ \\
S = \frac{-1}{9}\left(-572.4 \pm 572.4 e^{-9t/1060}\right)$

But only (+) satisfies $S(0) = 0$

$S= -\frac{1}{9}\left(-572.4 + 572.4 e^{-9t/1060}\right) \\ \\
S= 63.6 - 63.6 e^{-9t/1060}\text{ kg}$

Enter in S = 63.6 - 63.6 * e^(-9t/1060)

3 0

3 years ago