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2 years ago

Jylene and her brother had a total of $35.19 to buy school supplies. Jylene's school supplies cost

Mathematics

1 answer:

cricket20 [7]2 years ago

5 0

Answer:

13.31

Step-by-step explanation:

First do 35.19-12.78=22.41

I assume slightly more than $9 is .1

then subtract 22.41-9.1=13.31

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5<br>X Х please find the answer<br>20

Daniel [21]

Answer:

2 or 4

Step-by-step explanation:

Since I do not quite understand what you mean by X X, I could think of two answers. If you are doing 5 times X=20, then X = 4, but if you are trying to do 5 times x times x, then x=2.

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3 years ago

If a= 3+√5/2 then find the value of a square+1/a square

kondor19780726 [428]

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3 years ago

The function y = 4x + 3 describes Player A's

anyanavicka [17]

The rates of change of points earned by both players tell us that;

Player A gains more point than Player B does for each correct answer in this round.

We are told that x is the number of

number ofquestions answered correctly and y is the score.

Now, for player B;

For 1 correct answer, he got a score of 4

For 2 correct answers, he got a score of 5

For 3 correct answers, he got a score of 6

For 4 correct answers, he got a score of 7

This means that rate of change of Player B is;

3 points for every extra question answered correctly. .

Now, the formula for player A's points is;

y = 4x + 3

Rate of change of points here is gotten by finding the derivative. Thus;

dy/dx = 4

This means player A earns 4 points for every extra question answered correctly.

In conclusion, it mean that Player A gains more point than Player B does for each correct answer in this round.

Read more on slope intercept form of equation at; brainly.com/question/19249035

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2 years ago

Suppose James randomly draws a card from a standard deck of 52 cards. He then places it back into the deck and draws a second ca

qwelly [4]

Answer:

1.92%

Step-by-step explanation:

The probability for first case, picking a queen out of deck, will be:

$\frac{4}{52}$

as there will be 4 queens in a deck, one of each suit.

For the second pick, the probability of picking a diamond card, will be:

$\frac{13}{52}$

here the total will remain 52 as he has replaced the first card and not kept it aside and there will be 13 cards in diamond suit (including the three face cards).

Thus the net probability for both cases will be:

$P = \frac{4}{52} * \frac{13}{52}\\ P = \frac{1}{52}\\ P = 0.01923\\P = 1.923\%\\\\P = 1.92\%$

Thus total probability for the combined two cases will be 1.92%

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2 years ago

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Paraphin [41]

I am pretty sure the answer is A.

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3 years ago

Read 2 more answers