ANSWER
![\frac{1}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20)
EXPLANATION
We want to find an odds ratio from a given probability, which is
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
We subtract the numerator 1 from the denominator 4 to obtain
![4- 1= 3](https://tex.z-dn.net/?f=4-%201%3D%203)
The answer is the number of unfavorable outcomes.
The Odds can then be expressed as
![1 : 3](https://tex.z-dn.net/?f=1%20%3A%203)
The ratio of favourable outcomes to unfavorable outcomes.
Or
We have the given I = 10^-1 and I₀ = 10^-12.
Simply plugging in the values to the equation, we have:
L = 10log(10^-1/10^-12)
L = 110 Db
The answer is D.
(I used a scientific calculator in solving for L).
4.50 is 450 percent
because it is greater than 1, we know it is more than 100%
Answer:
![\frac{2}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B9%7D)
Step-by-step explanation:
![{\textrm}{Total number of objects here} = 9](https://tex.z-dn.net/?f=%7B%5Ctextrm%7D%7BTotal%20number%20of%20objects%20here%7D%20%3D%209)
(2 spreadsheets, 3 databases and 4 presentations,
![{\textrm}({Total} = 2+3+4 = 9)](https://tex.z-dn.net/?f=%7B%5Ctextrm%7D%28%7BTotal%7D%20%3D%202%2B3%2B4%20%3D%209%3C%2Fstrong%3E%29%3Cstrong%3E)
![{\textrm}{No. of databases with an odd number} = 2 {\textrm}{(databases with number 1 and 3})](https://tex.z-dn.net/?f=%7B%5Ctextrm%7D%7BNo.%20of%20databases%20with%20an%20odd%20number%7D%20%3D%3C%2Fstrong%3E%20%3Cstrong%3E2%20%7B%5Ctextrm%7D%7B%28databases%20with%20number%201%20and%203%7D%29)
As not mentioned other wise equal chances of all the outcomes is assumed so, by the classical definition of probability,
P(The chosen item is a odd numbered database)
=![\frac{2}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B9%7D)