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pychu [463]
3 years ago
11

Use basic trigonometric identities to simplify the expression: 2 sin (x) cos (x) sec (x) csc (x) = ?

Mathematics
1 answer:
photoshop1234 [79]3 years ago
5 0

Answer:

2sin(x)*cos(x)*sec(x)*csc (x)=2

Step-by-step explanation:

Remember the identities:

sec(x)=\frac{1}{cos(x)}\\\\csc(x)=\frac{1}{sin(x)}

Ginven the expression:

2sin(x)*cos(x)*sec(x)*csc (x)

You need to substitute sec(x)=\frac{1}{cos(x)} and csc(x)=\frac{1}{sin(x)} into it:

2sin(x)*cos(x)*sec(x)*csc (x)=2sin(x)*cos(x)*\frac{1}{cos(x)}*\frac{1}{sin(x)}

Now, you need to simplify.

Remember that:

\frac{a}{b}*\frac{c}{d}=\frac{a*c}{b*d}

And:

\frac{a}{a}=1

Then, you get:

=\frac{2sin(x)*cos(x)}{cos(x)*sin(x)}}=2

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Grace folded clothes for 25mins then she worked on a puzzle for 45mins she started folding clothes at 8:20am what time did she f
Wittaler [7]

Answer:

9:30am

Step-by-step explanation:

Given data

Start time= 8:20am

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3 years ago
Write the equation of the line that is perpendicular to 3x+2y=8 and goes through the point (-5,2)
kifflom [539]

Answer:

\displaystyle y=\frac{2}{3}(x+5)+2

Step-by-step explanation:

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The given line can be expressed as:

\displaystyle y=-\frac{3}{2}x+4

We can see the slope of this line is m1=-3/2.

The slopes of two perpendicular lines, say m1 and m2, meet the condition:

m_1.m_2=-1

Solving for m2:

\displaystyle m_2=-\frac{1}{m_1}

\displaystyle m_2=-\frac{1}{-\frac{3}{2}}

\displaystyle m_2=\frac{2}{3}

Now we know the slope of the new line, we use the slope-point form of the line:

y=m(x-h)+k

Where m is the slope and (h,k) is the point. Using the provided point (-5,2):

\boxed{\displaystyle y=\frac{2}{3}(x+5)+2}

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4 years ago
Find the sum of the interior angle measures of the polygon
pshichka [43]
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Work Shown:

We have 9 sides of this polygon. See the diagram below. So n = 9

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S = 180(9-2)

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