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pychu [463]
3 years ago
11

Use basic trigonometric identities to simplify the expression: 2 sin (x) cos (x) sec (x) csc (x) = ?

Mathematics
1 answer:
photoshop1234 [79]3 years ago
5 0

Answer:

2sin(x)*cos(x)*sec(x)*csc (x)=2

Step-by-step explanation:

Remember the identities:

sec(x)=\frac{1}{cos(x)}\\\\csc(x)=\frac{1}{sin(x)}

Ginven the expression:

2sin(x)*cos(x)*sec(x)*csc (x)

You need to substitute sec(x)=\frac{1}{cos(x)} and csc(x)=\frac{1}{sin(x)} into it:

2sin(x)*cos(x)*sec(x)*csc (x)=2sin(x)*cos(x)*\frac{1}{cos(x)}*\frac{1}{sin(x)}

Now, you need to simplify.

Remember that:

\frac{a}{b}*\frac{c}{d}=\frac{a*c}{b*d}

And:

\frac{a}{a}=1

Then, you get:

=\frac{2sin(x)*cos(x)}{cos(x)*sin(x)}}=2

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