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Step2247 [10]
3 years ago
5

A soccer ball is placed 12 feet away from a goal post that measures 8ft high. You kick the ball and it hits the crossbar at the

top the goal. What was the angle of elevation of you kick?
Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0
tg(\theta)=\frac{8}{12}\\
\\
tg(\theta)=0.666... \rightarrow \theta\approx35^o
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I have no clue to what I even need to do.
Gre4nikov [31]

\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \cline{1-1} \theta =\frac{3\pi }{2}\\ s=\frac{5\pi }{2} \end{cases}\implies \cfrac{5\pi }{2}=r\cdot \cfrac{3\pi }{2}

\bf \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{3~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{5~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=r\implies \cfrac{5}{3}=r

4 0
3 years ago
Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
polet [3.4K]
Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.

Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

For the product to be a diagonal matrix,

a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g

Consider the following sets of values

a=1, \ \ b=2, \ \ c=3, \ \ d = 4, \ \ e=\frac{1}{3}, \ \ f=-1, \ \ g=-\frac{1}{4}, \ \ h=\frac{1}{2}

The the matrix product becomes:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
8 0
3 years ago
Read 2 more answers
A cylinder has a volume of 245 cubic units and a height of 5 units. The diameter of the cylinder is
Vikki [24]

Answer:

The diameter is twice that, or approx. 7.90 units.

Step-by-step explanation:

the equation for the volume of a cylinder of radius r and height h is

V = πr²h.  Here we need to calculate the diameter after having found the radius.  Solving V = πr²h for r², we get:

           V

r² = -----------

         πh

Substituting the given values, we obtain for r² the following:

         145 units³

r² = ------------------------  = 15.6 units²

       3.14159(5 units)

Taking the square root of both sides, we get:

r = √15.60, or approx. 3.95 units.

The diameter is twice that, or approx. 7.90 units.

3 0
3 years ago
Read 2 more answers
Can anyone help me out on this
Rashid [163]

Answer: y=x+60

So y=mx+b is slope intercept form

y=x+60

m=1/1 because we go equally up as we go right so just put x

b=60 because we start at 60

Hope this helps

4 0
3 years ago
If f​(x​)=x+11 and g(x)=3x^2​, find ​(f+​g)(x​) and ​(f+​g)(5​).
Stella [2.4K]
(f+g)(x) = f(x) + g(x) = x + 11 + 3x^2
(f+g)(5) = f(5) + g(5) = 5 + 11 +3(5^2) = 91
8 0
3 years ago
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