Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
For a), this is clearly a given as it is literally to the right of where it says “Given:”
For b), since ON bisects ∠JOH, this means that it splits it into two separate angles - JON and HON, which are similar due to that bisects mean that it splits it equally into two halves
For c), since NO is the same thing as NO, it is equal to itself
For d), since AAS (angle-angle-side) congruence states that if there are two angles that are congruent (proved in a) and b) ) as well as that a side is congruent (proved in c) ), two triangles are congruent
For e), since two triangles are congruent, every side must have one side that it matches up to in the other triangle. As the opposite side of angle H is JO and the opposite side of angle J is OH, and ∠J=∠H, those two are congruent. As JN and HN are the two sides left, they must be congruent.
Feel free to ask further questions!
Use the law of cosines to solve for angle A. Plug your known side length values into the equation a^2 = b^2 + c^2 – 2bc cos A.
Then use the law of sines to find angle B. (Sin A/a = Sin B/b = Sin C/c).
Because the two red angles within B are congruent, divide your angle measure in half.
From there, do the law of sines to solve for x. Good luck!
I hopes this helps
Answer:
C and B
Step-by-step explanation:
The correct option is option B and C. The necessary condition to prove that the opposite angles of a parallelogram are congruent:
C. Angle Addition Postulate.
B. Opposite sides are congruent
Answer:
25 miles
Explanation:
We can use Pythagoras’ theorem for this
