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True [87]
3 years ago
14

if you randomly place these five CDs on a 5-disc rack, what are the chances that you will place them alphabetically by artist?

Mathematics
2 answers:
aliina [53]3 years ago
4 0

Answer: 1/120

Step-by-step explanation:

There are 5! = 120 ways to place these disks, but only one of them will have them alphabetical by artist. So, if you randomly choose one of these ways, there will be a 1/120 chance you placed them alphabetically by artist.

Dmitriy789 [7]3 years ago
3 0

Answer:

The chances are high beceuse their are only a few disks and the would be easy to put in alphabetically by artist

Step-by-step explanation:

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All rectangles are paralloelograms
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not all rectangles are paralloelograms.

Step-by-step explanation:

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2 years ago
4 (x+2) as a word phrase
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Four times the sum of x and two
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9100 dollard placed into an account with an annual intrest of 5% to the neareast year how long will it take for the account to v
shusha [124]

Answer:

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Step-by-step explanation:

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3 years ago
7y-4y+2=<br> What’s the answer?
Kay [80]

Answer:

3y + 2 =

Step-by-step explanation:

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3 0
2 years ago
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find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}
inn [45]
Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
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Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2  and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2      and  x" = [10 - √64]/2

x' = (10+12)/2    and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity


6 0
3 years ago
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