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Paladinen [302]
2 years ago
14

Bored? Get your brain exercised with a TRICKY MATH question!

Mathematics
1 answer:
Katena32 [7]2 years ago
7 0

Answer:

the \: answer \: i s \: 89100000 \\ to \: be \: honest \: it \: wasnt \: that \: hard

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Find the measure of < AED for m < BEC = 96
Strike441 [17]
I wish you would of put a picture but with what you gave me. if the angle is a straight line then you would just set it up like 96+x=180 bc a straight line ='s 180 and den subtract 96 from 180 which is 84 so x would = 84 if the angle is a supp. angle but til there's not a picture this might be wrong.
But i hope this helps have a nice nite!
5 0
3 years ago
Read 2 more answers
7/16 in decimal form​
neonofarm [45]

Answer:

0.4375

Step-by-step explanation:

8 0
3 years ago
21 trucks, each with a 2.5-ton payload, are needed to unload a freight train. How many trucks, each with a 3.5-ton payload, woul
castortr0y [4]
Tons needed to unload a freight train= 21×2.5 =52.5
number of 3.5-ton payload trucks needed to unload a freight train=52.5÷3.5 = 15

15 Trucks , Each With A 3.5-Ton Payloaf , Would be Needed To Do The Same Job. 

6 0
3 years ago
if your bag of M&M’s has 8 yellow out of 24 , how many of them will be yellow i’d the bag has a total of 96?
Lera25 [3.4K]

Answer: 32

Step-by-step explanation:

96 divided by 24 is 4

8x4=32

7 0
3 years ago
Southern Oil Company produces two grades of gasoline: regular and premium. The profit contributions are $0.30 per gallon for reg
Contact [7]

Answer:

a) MAX--> PC (R,P) = 0,3R+ 0,5P

b) <u>Optimal solution</u>: 40.000 units of R and 10.000 of PC = $17.000

c) <u>Slack variables</u>: S3=1000, is the unattended demand of P, the others are 0, that means the restrictions are at the limit.

d) <u>Binding Constaints</u>:

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

Step-by-step explanation:

I will solve it using the graphic method:

First, we have to define the variables:

R : Regular Gasoline

P: Premium Gasoline

We also call:

PC: Profit contributions

A: Grade A crude oil

• R--> PC: $0,3 --> 0,3 A

• P--> PC: $0,5 --> 0,6 A

So the ecuation to maximize is:

MAX--> PC (R,P) = 0,3R+ 0,5P

The restrictions would be:

1. 18.000 A availabe (R=0,3 A ; P 0,6 A)

2. 50.000 capacity

3. Demand of P: No more than 20.000

4. Both P and R 0 or more.

Translated to formulas:

Answer d)

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

To know the optimal solution it is better to graph all the restrictions, once you have the graphic, the theory says that the solution is on one of the vertices.

So we define the vertices: (you can see on the graphic, or calculate them with the intersection of the ecuations)

V:(R;P)

• V1: (0;0)

• V2: (0; 20.000)

• V3: (20.000;20.000)

• V4: (40.000; 10.000)

• V5:(50.000;0)

We check each one in the profit ecuation:

MAX--> PC (R,P) = 0,3R+ 0,5P

• V1: 0

• V2: 10.000

• V3: 16.000

• V4: 17.000

• V5: 15.000

As we can see, the optimal solution is  

V4: 40.000 units of regular and 10.000 of premium.

To have the slack variables you have to check in each restriction how much you have to add (or substract) to get to de exact (=) result.  

3 0
2 years ago
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