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mel-nik [20]
3 years ago
13

I NEED HELP ASAPPPPPP

Mathematics
1 answer:
andreev551 [17]3 years ago
7 0

Answer:

A reflection fallowed by a translation. Im pretty sure

Step-by-step explanation:

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Which statement describes this pair of congruent triangles?
Volgvan
NLM bc the angled correspond, making the triangles congruent
7 0
3 years ago
If a+b+b =24 and b-a =4 what is a?​
Lyrx [107]

Answer:

a = 5 1/3

Step-by-step explanation:

a+b+b = 24

a + 2b = 24

b-a =4

a = b - 4

b - 4 + 2b = 24

3b = 24 + 4

b =28/3

substitute this in a = b - 4

a = 28/3 - 4

a = 28/3 - 12/3

a = 16/3

a = 5 1/3

3 0
3 years ago
Read 2 more answers
Find the maximum and minimum values attained by f(x, y, z) = 5xyz on the unit ball x2 + y2 + z2 ≤ 1.
Allushta [10]
Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
f_x=5yz=0\implies y=0\text{ or }z=0
f_y=5xz=0\implies x=0\text{ or }z=0
f_z=5xy=0\implies x=0\text{ or }y=0


Taken together, we find that (0, 0, 0) appears to be the only critical point on f within the ball. At this point, we have f(0,0,0)=0.

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)

with partial derivatives (set to 0)

L_x=5yz+2\lambda x=0
L_y=5xz+2\lambda y=0
L_z=5xy+2\lambda z=0
L_\lambda=x^2+y^2+z^2-1=0

We then observe that

xL_x+yL_y+zL_z=0\implies15xyz+2\lambda=0\implies\lambda=-\dfrac{15xyz}2

So, ignoring the critical point we've already found at (0, 0, 0),


5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}
5xz+2\left(-\dfrac{15xyz}2\right)y=0\implies5xz(1-3y^2)=0\implies y=\pm\dfrac1{\sqrt3}
5xy+2\left(-\dfrac{15xyz}2\right)z=0\implies5xy(1-3z^2)=0\implies z=\pm\dfrac1{\sqrt3}

So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of \left(\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3}\right), at which points we get a value of either of \pm\dfrac5{\sqrt3}, with the maximum being the positive value and the minimum being the negative one.
5 0
3 years ago
PLEASE HELP ME ASAP ILL GIVE 100 POINTS
Airida [17]

Answer:

8(+4)

Step-by-step explanation:

6 0
3 years ago
Is a acute triangle regular?
mixas84 [53]

Answer:

An equilateral triangle may also be called a "regular" triangle. (A "regular" polygon has all equal sides and all equal angles.)An acute triangle has all angles measuring less than 90º. Note: It is possible for an acute triangle to also be scalene, isosceles, or equilateral.

Step-by-step explanation:

hope this helped and can u plz mark me brainlest

7 0
3 years ago
Read 2 more answers
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