Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
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Complete Question
Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150
Answer:
Normal sampling distribution can not be used
Step-by-step explanation:
From the question we are told that
The null hypothesis is 
The alternative hypothesis is 
The sample size is n= 150
Generally in order to use normal sampling distribution
The value 
So


Given that
normal sampling distribution can not be used
3n-5=-48-40n
Move -40n to the other side. Sign changes from -40n to +40n.
3n+40n-5=-48= -48-40n+40n
3n+40n-5=-48
Move -5 to the other side.
3n+40n-5+5=-48+5
3n+40n=-43
43n=-43
Divide by 43 for both sides
43n/43=-43/43
n=-1
Answer: n=-1