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marta [7]
3 years ago
8

An athlete jumped 5.5 feet which was 1.1 times higher than the previous jumper how high did the previous athlete jump

Mathematics
2 answers:
saw5 [17]3 years ago
6 0

Answer:

5 ft

Step-by-step explanation:

The previous jumper jumped p

The new jumper jumped p*1.1 and that was 5.5 ft

1.1p = 5

Divide each side by 1.1

1.1p/1.1 = 5.5/1.1

p = 5

The previous jumper jumped 5 ft

Fantom [35]3 years ago
3 0

Answer:

5 ft

Step-by-step explanation:

Let the height of the previous jump be represented by j.  Then 1.1j = 5.5 ft.

Dividing both sides by 1.1, we get j = 5 ft.  This was the height of the previous jump.

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Mariana [72]
4 I just took the quiz
4 0
3 years ago
Considere a função de oferta como sendo y= 5x - 1/2 e a função de demanda como sendo y= -7x + 47/2 , onde x é a quantidade e y é
swat32

A) Temos que igualar isso a 2,50, que é o valor de y, ou seja, o valor do preço. Façamos isso, então, na função de demanda.

y = -7x + \frac{47}{2}

Substituir.

2,50 = - 7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x  = - \frac{47}{2} + 2,50

A fração 47/2 corresponde a 23,5. É mais interessante para nós, nesse caso, utilizar o valor decimal.

-7x  = - 23,5 + 2,50

Somar logo.

-7x = -21

Podemos multiplicar por -1 para tirar os sinais negativos.

7x = 21

Passar o x dividindo

x = \frac{21}{7}

Dividir

\boxed{x = 3}

Para um preço de R$ 2,50, a quantidade demandada é de 3 unidades.



B) Basta igualar as duas formulinhas.

5x - \frac{1}{2} = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x + 7x = \frac{47}{2} + \frac{1}{2}

Somar tudo. Como as frações têm o mesmo denominador, <u>nada de </u><u>mmc</u>! Basta somar os numeradores.

12x = \frac{48}{2}

Podemos dividir lá, olha:

12x = 24

Passar o x dividindo

x = \frac{24}{12}

Dividir

\boxed{x = 2}

O ponto de equilíbrio é o valor 2.



C) Basta, então, igualar as fórmulas da oferta e da demanda a 10.

Fórmula da oferta

10 = 5x - \frac{1}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x = 10 - \frac{1}{2}

Se 1/2 = 0,5, dá pra resolver sem fazer mmc:

5x = 10 - 0,5

Subtrair

5x = 9,5

Passar dividindo

x = \frac{9,5}{5}

Dividir.

\boxed{x = 1,9}

Fórmula da demanda

10 = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x = \frac{47}{2} - 10

Divide 47/2, vai.

-7x = 23,5 - 10

Subtrair.

-7x = 13,5

Passar o 7 dividindo.

x = - \frac{13,5}{7}

Vamos dividir e transformar em decimal.

\boxed{x = -1,9285714285714285714285714285714}


Subtrair a oferta pela demanda.

x = 1,9 - (-1,9285714285714285714285714285714)

Subtrair.

\boxed{x = 3,8285714285714285714285714285714}

Arredondando, o preço será de R$ 3,83.

8 0
3 years ago
Find the value of :[5x+y+z][5x+y+z][5x+y+z]
KIM [24]

Answer:

Step-by-step explanation:

(a + b + c)³ = a³ + b³ + c³ + 3a²b + 3a²c + 3ab² + 3cb² +3 ac² + 3bc² + 6abc

a = 5a  ;  b =y   ; c = z

(5x + y + z)(5z + y + z )(5z + y +z) = (5x + y +z)³

= (5x)³ + y³ +z³ + 3(5x)²y + 3(5x)²z + 3(5x)*y² + 3*z*y² + 3*5x*z² + 3*y*z² + 6*5x*y*z

= 125x³ + y³ +z³ + 3*25x²y + 3*25x²*z + 15xy² + 3zy² + 15xz² + 3yz² + 35xyz

= 125x³ + y³ + z³ + 75x²y + 75x²z + 15xy² + 3zy² + 15xz² + 3yz² + 35xyz

6 0
3 years ago
9err9jwihwr9ihwrighiwrrghihsrhrgishfgisif10101
Svetllana [295]

Answer:

yes

Step-by-step explanation:

...

3 0
3 years ago
What is the value of the expression? −3/4+(1/10÷2/5) Enter your answer, as a fraction in simplest form, in the box.
blagie [28]
-11/20 would be the value of the expression
8 0
3 years ago
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