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prisoha [69]
3 years ago
13

-29=5u+6-12u solve for you

Mathematics
2 answers:
liberstina [14]3 years ago
8 0

Answer:

Step-by-step explanation:

5u - 12u + 6 = -29

-7u + 6 = -29

-7u = -35

u = 5

scoray [572]3 years ago
3 0

Answer:

u=5

Step-by-step explanation:

5u+6-12u=-29

5u-12u+6=-29

-7u+6=-29

-7u=-29-6

-7u=-35

-7u/-7=-35/-7

u=-35/-7

u=5

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Step-by-step explanation:

5 0
3 years ago
Simplify square root of ten times square root of eight.
Romashka-Z-Leto [24]
<h2>Explanation:</h2><h2></h2>

Here we need to simplify the square root of ten times square root of eight, so let's write this step by step:

Step 1. The square root of ten

\sqrt{10}

Step 2. The  square root of eight

\sqrt{8}

Step 3. The square root of ten times square root of eight

\sqrt{10}\times \sqrt{8} \\ \\ \\ \text{From radical property:} \\ \\ \sqrt{a}\times \sqrt{b}=\sqrt{ab} \\ \\ \\ So: \\ \\ \sqrt{10}\times \sqrt{8}=\sqrt{80} \\ \\ \\ But: \\ \\ \sqrt{80}=\sqrt{16\time5}=\sqrt{16}\sqrt{5}=4\sqrt{5}

Finally, the correct option is:

<em>Four square root of five</em>

4 0
3 years ago
Read 2 more answers
I need the mean, medium, and the mode for these numbers [4,10,11,15,16,16,18,19]​
iren [92.7K]

Hello here would be your answers:

mean: 13.6  

mediun: 15.5  

mode: 16

remember it like this

Mean is the average

Mode is the most often number

Range is when you subtract the smallest number from the largest number

Medium is the middle number when you line it up from the greatest to the least.

hope this helps!

7 0
3 years ago
C is 8 more than half than n
cestrela7 [59]
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7 0
4 years ago
What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE
Nutka1998 [239]

Answer:

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),  \left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

Step-by-step explanation:

Let points D, E and F have coordinates (x_D,y_D),\ (x_E,y_E) and (x_F,y_F).

1. Midpoint M of segment DF has coordinates

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).

2. Midpoint N of segment EF has coordinates

\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0
3 years ago
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