Question

a shot putter releases the shot some distance above the level ground with a velocity of 12.0 m/s, 51.0 ∘above the horizontal. the shot hits the ground 2.08 s later. you can ignore air resistance. how far did she throw the shot?

Answer 1

Answer:

15.7 m

Explanation:

The range (horizontal distance) of the projectile is determined only by its horizontal motion.

The horizontal motion is a motion with constant speed, which is equal to the initial horizontal velocity of the object:

$v_x = v cos \theta$

where

v = 12.0 m/s is the initial velocity

$\theta=51.0^{\circ}$ is the angle between the direction of v and the horizontal

Substituting,

$v_x = (12.0 m/s)(cos 51.0^{\circ} )=7.55 m/s$

We know that the projectile hits the ground in a time of

t = 2.08 s

so the horizontal distance covered is

$d = v_x t = (7.55 m/s)(2.08 s)=15.7 m$