Answer:
-4*10⁴ units.
Explanation:
As the metal rod was initially neutral (which means that it has the same quantity of positive and negative charges), after being close to the charged sphere, as charge must be conserved, the total charge of the metal rod must still remain to be zero.
So, if due to the influence of the negative charge in the sphere, the half of the road closer to the sphere has a surplus charge of +4*10⁴ units, the charge on the half of the rod farther from the sphere must be the same in magnitude but of the opposite sign, i.e., -4*10⁴ units.
Answer:
Explanation:
is the angle between the velocity and the magnetic field. So, the magnetic force on the proton is:
A charged particle describes a semicircle in a uniform magnetic field. Therefore, applying Newton's second law to uniform circular motion:
is the centripetal force and is defined as:
Here 
is the proton's speed and 
is the radius of the circular motion. Replacing this in (1) and solving for r:
Recall that 1 J is equal to 
, so:
We can calculate from the kinetic energy of the proton:
Finally, we calculate the radius of the proton path:
Answer: 0.00000938422m^3
Explanation:
dV=Vø*β*(t1-tø)
The parameters are
dV is the change in volume after temperature increase
Vø =0.607 *10^-3m3 is the initial vokume of coffe at 16.2^0 C
β= coefficient of volume expansion of water at 16.2^0 C is 0.0002/0C
t1= 93.5^0C final temperature
tø=16.2^0 C
Therefore
dV=0.607 *10^-3 *0.0002*(93.5-16.2)
dV= 0.00000938422m^3
This is the volume of coffee that will spill over the container
