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Helen [10]
3 years ago
14

If a ball rolls at constant velocity, it is rolling at constant speed? explain

Physics
1 answer:
Shtirlitz [24]3 years ago
7 0
Velocity is speed with direction. So, if velocity varies directly with speed, that statement would be true. A constant velocity would resort in a constant speed. They are connected and are dependant on each other.

I hope this helps!
~kaikers
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A soap bubble is essentially a thin film of water surrounded by air. The colors you see in soap bubbles are produced by interfer
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What happens when waves encounter a medium that they cannot travel through
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Then the waves (and the energy they carry) are completely reflected from the surface of the impenetrable medium.

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3 years ago
A 12.0-V emf automobile battery has a terminal voltage of 16.0 V when being charged by a current of 10.0 A. (a) What is the batt
forsale [732]

Answer:

(a) the battery’s internal resistance is 0.4 Ω

(b) the dissipated power dissipated inside the battery is 40 W

(c) the  rate 0.096°C/min

Explanation:

Given information:

emf, ε = 12 V

voltage, V = 16 V

current, I = 10 A

mass, m = 20 kg

specific heat, c = 0.300 kcal/kg°C = 1255.8 J/kg°C

(a) What is the battery’s internal resistance?

to calculate the internal resistance, we can calculate by using the following formula

V = ε - Ir

where

V = voltage (V)

I = current (A)

r = internal resistance (Ω)

ε = emf (V)

since the battery is being charged, the current is negative, so

V = ε - (-I) r

V = ε + Ir

r = (V- ε)/I

 = (16 - 12)/10

 = 0.4 Ω

(b) What power is dissipated inside the battery?

to determine the dissipated power in the battery, use the following equation

P = I²r

where

P = power (W)

P = (10)² (0.4)

  = 40 W

(c) At what rate (in °C/min ) will its temperature increase if its mass is 20.0 kg and it has a specific heat of 0.300kcal/kg⋅°C , assuming no heat escapes

to find the rate of temperature increase by

Q = m c ΔT

where

Q = thermal energy (J)

c = specific heat (J/kg°C)

ΔT = the change of temperature

to find the energy, we use

E = Pt

the energy is converted in one minute

E = 40 x 60

  = 2400 J

thus,

2400 = 20 x 1255.8 x ΔT

ΔT = 2400/(20 x 1255.8)

     = 0.096°C/min

3 0
3 years ago
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