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3 years ago

How can you increase the intensity of sound waves

Physics

1 answer:

VladimirAG [237]3 years ago

5 0

Answer

The intensity of a sound wave depends on the pressure of the wave,density of the medium and speed of sound in the medium. Higher density and higher sound speed both give a lower intensity. and may be it is because that sound wave is more characterize by wavelength than frequency..explanation

Explanation:

As decibel levels get higher, sound waves have greater intensity and sounds are louder. For every 10-decibel increase in the intensity of sound, loudness is 10 times greater. Intensity of sound results from two factors: the amplitude of the sound waves and how far they have traveled from the source of the sound.

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Anyone know this... pls help its for a grade

hodyreva [135]

His average speed is 45 miles an hour

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3 years ago

After a student shoves a book across a flat table, it begins to slow down. Why?

Dovator [93]

Answer:

<u>The force of friction opposes the motion of an object, causing moving objects to lose energy and slow down. When objects move through a fluid, such as air or water, the fluid exerts a frictional force on the moving object. The frictional force from a fluid is called a drag force.</u>

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3 years ago

A 0.12-mu or micro FF capacitor, initially uncharged, is connected in series with a 10-kohm resistor and a 12-V battery of negli

miv72 [106K]

Answer:

The time is 2.8 ms.

Explanation:

Given that,

Capacitor = 0.12 μF

Resistance = 10 kohm

Voltage = 12 V

Charge Q = 0.9 Q₀

We need to calculate the time constant

Using formula of time constant

$T=RC$

Put the value into the formula

$T=10\times10^{3}\times0.12\times10^{-6}$

$T=0.0012\ sec$

We need to calculate the time

Using formula of time

$Q=Q_{0}(1-e^{\frac{-t}{T}})$

Put the value into the formula

$0.9Q_{0}=Q_{0}(1-e^{\frac{-t}{0.0012}})$

$ln (0.1)=\dfrac{-t}{0.0012}$

$t=0.00276\ sec$

$t=2.8\ ms$

Hence, The time is 2.8 ms.

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4 years ago

car 1 is traveling south at 18 m/s and has a full load, giving it a total mass of 14,650 kg. Car 2 is traveling north at 11 m/s

kvasek [131]

Answer:

v_{4}= 80.92[m/s] (Heading south)

Explanation:

In order to calculate this problem, we must use the linear moment conservation principle, which tells us that the linear moment is conserved before and after the collision. In this way, we can propose an equation for the solution of the unknown.

ΣPbefore = ΣPafter

where:

P = linear momentum [kg*m/s]

Let's take the southward movement as negative and the northward movement as positive.

$-(m_{1}*v_{1})+(m_{2}*v_{2})=-(m_{1}*v_{3})+(m_{2}*v_{4})$

where:

m₁ = mass of car 1 = 14650 [kg]

v₁ = velocity of car 1 = 18 [m/s]

m₂ = mass of car 2 = 3825 [kg]

v₂ = velocity of car 2 = 11 [m/s]

v₃ = velocity of car 1 after the collison = 6 [m/s]

v₄ = velocity of car 2 after the collision [m/s]

$-(14650*18)+(3825*11)=(14650*6)-(3825*v_{4})\\v_{4}=80.92[m/s]$

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3 years ago

What is the key difference between a liquid and a gas?

marissa [1.9K]

<span>a. intermolecular attractions.............</span>

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3 years ago

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