Question

In triangle ABC, angle A= 74, a = 126, and b= 84. Find angle B

Answer 1

Answer:

Angle B = 39.85°

Step-by-step explanation:

We have sine formula

         $\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}$

Here A = 74°, a = 126 and b =84

Substituting

            $\frac{126}{sin74}=\frac{84}{sinB}\\\\sinB=0.6408\\\\B=39.85^0$

Angle B = 39.85°

Answer 2

Angle B is 39.855°, hope this helps