Question

Question 18 (1 points) A step-up transformer connected to a 110-V line is used to supply a hydrogen-gas discharge tube with 5.0 kV (rms). The tube dissipates 75 W of power. What is the ratio of the number of turns in the secondary winding to the number of turns in the primary winding?

Answer 1

Answer:

N₂/N₁ = 45

Explanation:

The relation of the number of turns with the voltage is given by the EMF equation of transformer:  

$\frac{V_{2}}{V_{1}} = \frac{N_{2}}{N_{1}}$ (1)

where V₁: voltage of the primary winding, V₂: voltage of the secondary winding, N₁: number of turns in the primary winding, and N₂: number of turns in the secondary winding

Assuming that the primary winding is connected to the input voltage supply, and using equation (1), we can calculate the ratio of N₂ to N₁:

$\frac{N_{2}}{N_{1}} = \frac{V_{2}}{V_{1}} = \frac{5.0 \cdot 10^{3}V}{110V} = 45$       

So, the ratio N₂/N₁ is 45.

Have a nice day!