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Bogdan [553]
3 years ago
8

All of the following elements produce magnetic fields except

Physics
2 answers:
Darya [45]3 years ago
8 0

Answer:

If you have these choices:

a. nickel. b. cobalt c. iron  d. copper,

then the answer would be D. copper :))

KatRina [158]3 years ago
6 0
The answer should be copper. hope this helps :D
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Children are ready for more complex storybooks:
FromTheMoon [43]

Answer:

4

Explanation:

Because that is when they're mind learns how to read

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3 years ago
Airplanes moves in blank dimensions through. <br><br> What is Blank
raketka [301]
Blank is something empty lol
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3 years ago
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Two 2.0-cm-diameter insulating spheres have a 6.60 cm space between them. One sphere is charged to + 76.0 nC , the other to - 30
e-lub [12.9K]

Answer:

5.2\times 10^5N/C

Explanation:

Since the two charged bodies are symmetric, we can calculate the electric field taking both of them as point charges.

This can be easily seen if we use Gauss's law, \int{E} \, dA=\frac{Q_{enclosed}}{\epsilon_o}

We take a larger sphere of radius, say r, as the Gaussian surface. Then the electric field due to the charged sphere at a distance r from it's center is given by,

E=\frac{1}{4\pi r^2} \frac{Q_{enclosed}}{\epsilon_o}

which is the same as that of a point charge.

In our problem the charges being of opposite signs, the electric field will add up. Therefore,

E_{total}=\frac{1}{4\pi\epsilon_o}\frac{q_1+q_2}{r^2}= (9\times10^9) \frac{(76+30)\times10^{-9}}{((1+3.3)\times10^{-2})^2}N/C =5.2\times10^5N/C

where, r = distance between the center of one sphere to the midpoint (between the 2 spheres)

8 0
3 years ago
A person standing on a scale feels a normal force of 655 N pushing up on him. What is his mass? (Unit=kg)
dimulka [17.4K]

Answer:

Approximately 66,8kg

Hope this help :D

Explanation:

F=mg. So 655N= 9.8 m/s² × mass.

Mass = 655 / 9.8

3 0
4 years ago
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At an accident scene on a level road, investigators measure a car’s skid mark to be 88 m long. The accident occurred on a rainy
Oduvanchick [21]

Answer:

The the speed of the car is 26.91 m/s.

Explanation:

Given that,

distance d = 88 m

Kinetic friction = 0.42

We need to calculate the the speed of the car

Using  the work-energy principle

work done = change in kinetic energy

W=\Delta K.E

\mu\ mg\times d=\dfrac{1}{2}mv^2

v^2=2\mu g d

Put the value into the formula

v=\sqrt{2\times0.42\times9.8\times88}

v=26.91\ m/s

Hence, The the speed of the car is 26.91 m/s.

3 0
3 years ago
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