Answer:
3.7 m
Explanation:
ASSUMING this means extra distance beyond where the cannonball would land WITHOUT the wind assistance but in general ignoring air resistance. Hmmmmmm...tricky
The ball drops from vertical rest to ASSUMED horizontal ground 15 m below in a time of 
t = √ (2h/g) = √(2(15)/9.8) = 1.75 s
Without the tail wind, the ball travels horizontally
d = vt = 68(1.75) = 119 m
The tailwind exerts a constant acceleration on the ball of 
a = F/m = 12/5.0 = 2.4 m/s²
The average horizontal velocity during the flight is
v(avg) = (68 + (68 + 2.4(1.75)) / 2 = 70.1 m/s
so the distance with tailwind is
d = v(avg)t = 70.1(1.75) = 122.675 m
The extra distance is 122.675 - 119 = 3.675 = 3.7 m
 
        
             
        
        
        
Answer:
3.33 minutes (3 minutes and 20 seconds)
Explanation:
Speed of the runner = s = 5 m/s
We need to calculate how will it take for runner to complete 1 km. We have the speed, the distance and we need to find the time. Before performing any calculations, we must convert the values to same units.
Speed is in m/s and distance is in kilometers. So we have to either convert speed to km/s or distance into meters. In this case, converting distance into meters would be a convenient option.
1 kilo meters = 1000 meters
The distance, speed and time are related by the equation:
Distance = Speed x Time
So,
Time = Distance/Speed
Using the values, we get:
t = 1000/5 
t = 200 seconds
This means, the runner can complete 1 kilometers in 200 seconds. Since, there are 60 seconds in a minute, we can convert this time to minutes, by dividing it by 60. i.e.

Thus, it will take the runner 3.33 minutes (3 minutes and 20 seconds) to travel 1 km.
 
        
             
        
        
        
Answer:
Conductivity probe 
Explanation:
The Conductivity Probe consists of two electrodes(also referred to as probes)or an electrode and a wall vessel where the material in the vessel completes the circuit as the level rises in the vessel.
It is used in measuring solution conductivity or total ionic concentration of aqueous samples.