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2 years ago

Hey intelligent ppl... pls help?!

Mathematics

2 answers:

Lerok [7]2 years ago

4 0

Answer:

YW=7 because it is congruent to the other bisector ZX.

dsp732 years ago

3 0

Answer: YW=7

Step-by-step explanation:

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The cost of having t-shirts printed at two different shops is displayed below. Use the information provided to answer the follow

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Answer:

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3 years ago

Help no troll answer plz

stealth61 [152]

Answer:

Step-by-step explanation:

Q 4. (25m + 25m) ÷ 25 sec. = 2 m/sec.

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7 0

3 years ago

Rationalize the numerator. <img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B144x%20%7D%20%7D%7B%20%5Csq

Simora [160]

rationalizing the numerator, or namely, "getting rid of that pesky radical at the top".

we simply multiply top and bottom by a value that will take out the radicand in the numerator.

$\bf \cfrac{\sqrt[3]{144x}}{\sqrt[3]{y}}~~
\begin{cases}
144=2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 3\\
\qquad 2^3\cdot 18
\end{cases}\implies \cfrac{\sqrt[3]{2^3\cdot 18x}}{\sqrt[3]{y}}\implies \cfrac{2\sqrt[3]{ 18x}}{\sqrt[3]{y}}
\\\\\\
\cfrac{2\sqrt[3]{ 18x}}{\sqrt[3]{y}}\cdot \cfrac{\sqrt[3]{(18x)^2}}{\sqrt[3]{(18x)^2}}\implies \cfrac{2\sqrt[3]{(18x)(18x)^2}}{\sqrt[3]{(y)(18x)^2}}\implies \cfrac{2\sqrt[3]{(18x)^3}}{\sqrt[3]{18^2x^2y}}$

$\bf \cfrac{2(18x)}{\sqrt[3]{324x^2y}}~~
\begin{cases}
324=2\cdot 2\cdot 3\cdot 3\cdot 3\cdot 3\\
\qquad 12\cdot 3^3
\end{cases}\implies \cfrac{36x}{\sqrt[3]{12\cdot 3^3x^2y}}
\\\\\\
\cfrac{36x}{3\sqrt[3]{12x^2y}}\implies \cfrac{12x}{\sqrt[3]{12x^2y}}$

3 0

3 years ago

Read 2 more answers

Find the HCF of 150 and 180.

Ratling [72]

Answer:

30 is ans do you know hindi

3 0

2 years ago

Read 2 more answers

(f/g)(x)and (f/g)(7)

Phoenix [80]

Answer:

$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}$

Step-by-step explanation:

Division operation of function: $If\ f(x)\ and\ g(x)\ are\ two\ functions\ then\ (\frac{f}{g})(x)=\frac{f(x)}{g(x)}$

$Here\ we\ have\ to\ find\ (\frac{f}{g})(7)\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}$

Example:

$Take\ f(x)=3x^2+1,\ g(x)=x+1\\\\(\frac{f}{g})(x)=\frac{f(x)}{g(x)}\\\\(\frac{f}{g})(x)=\frac{3x^2+1}{x+1}\\\\f(7)=3\times 7^2+1\\\\f(7)=3\times 49+1\\\\f(7)=148\\\\g(7)=7+1\\\\g(7)=8\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}\\\\(\frac{f}{g})(x)=\frac{148}{8}$

7 0

3 years ago