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3 years ago

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Chemistry

1 answer:

Feliz [49]3 years ago

7 0

Answer:

Explanation:

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Given the NaOH density =1.0698g mL^-1, How many mL of .71M HCl would be required to neutralize 11.33g of 2.03 M NaOH?

SSSSS [86.1K]

The volume in ml of 0.71 M HCl that would be required to neutralize 11.33 g of 2.03 M NaOH is 30.3 ml

<u><em>calculation</em></u>

Step 1 : write equation for reaction

NaOH + HCl →NaCl +H₂O

Step 2:find the volume of NaOH

volume=mass/ density

= 11.33 g/ 1.0698 g/ml =10.59 ml

Step 3: find the moles of NaOH

moles = molarity x volume in liters

molarity= 2.03 M=2.03 mol/l

volume in liters =10.59/1000 =0.0106 L

moles = 2.03 M x 0.0106 L =0.0215 moles

step 4: use the mole ratio to determine the moles of HCl

from equation in step 1 , NaOH:HCl is 1:1 therefore the moles of HCl is also 0.0215 moles

Step 5: find volume of HCl

volume= moles/ molarity

molarity =0.71 M =0.71 mol/l

=0.0215 moles /0.71 mol/l=0.0303 L

into ml =0.0303 x 1000=30.3 ml

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3 years ago

______ is the maximum population an area can support on a long-term basis without experiencing negative effects.

Alika [10]

Answer:

carrying capacity

Explanation:

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3 years ago

What is the oh- in a solution with a poh of 5.71

Rudik [331]

Answer:- The hydroxide ion concentration of the solution is $1.95*10^-^6$ .

Solution:- The formula used to calculate pOH from hydroxide ion is:

$pOH=-log[OH^-]$

When pOH is given and we are asked to calculate hydroxide ion concentration then we multiply both sides by negative sign and take antilog and what we get on doing this is:

$[OH^-]=10^-^p^O^H$

pOH is given as 5.71 and we are asked to calculate hydrogen ion concentration. Let's plug in the given value in the formula:

$[OH^-]=10^-^5^.^7^1$

$[OH^-]$ = 0.00000195 or $1.95*10^-^6$

So, the hydroxide ion concentration of the solution is $1.95*10^-^6$ .

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3 years ago

Pls Help with this Chemistry question

Monica [59]

A decrease in n emits energy and an increase absorbs energy. This mean the greater the decrease the greater amount energy is being emitted. So the answer should be:
A. n=5 to n=1

Really hopes this helps!

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4 years ago

The most common form of energy encountered in chemical reactions is _____. Select one:

Svetllana [295]

The answer is b heat

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3 years ago