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Anuta_ua [19.1K]
3 years ago
5

In the United States, there were approximately 1,664 ride-related injuries in fixed-site amusement parks in 2007, compared to 1,

797 in 2006. Use an exponential function to determine the ride related injuries in 2016, and discuss the reasonableness of the result.
771; exponential models are useful short-term, but not long-term: not reasonable.

833: reasonable

833; exponential models are useful short-term, but not long-term: not reasonable.

3,880; exponential models are useful short-term, but not long-term: not reasonable.
Mathematics
2 answers:
motikmotik3 years ago
8 0
The decrease in injuries from 2006 and 2007 is a reduction factor of about 7.4%. If we use this factor to predict the number of injuries in 2016, we get 0.926¹⁰=0.463 approx as a reduction factor to be applied to the 2006 data. So 0.463×1797=833 approx. Is this reasonable? I don’t think so because the prediction is based on too few figures. 10 years is fairly long term compared to the short term of a year between 2006 and 2007. To be reasonable data is needed for other years. So answer 3 seems the best answer.
Mashutka [201]3 years ago
6 0
Hello,

<span> exponential models are useful short-term, but not long-term: not reasonable
</span>

Hope this helps
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3 years ago
I'm studying a new bacteria that doubles in numbers every 25 minutes. If i start with 50 bacteria, how long until i have 5 milli
dimaraw [331]

Answer:

415.63 minutes

Step-by-step explanation:

Growth can be represented by the equation A=A_0e^{rt}. We can find the rate at which it grows by using t=25 minutes and \frac{A_{0}}{A} =2 or double the amount at that time. The first step we always take is to divide A_0 by A.

[tex]\frac{A_{0}}{A}=e^{rt}\\2=e^{r(25)}

2=e^{(25)r}

To solve for r, we will take the natural log of both sides and use log rules to isolate r.

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We know lne=1 so we were able to cancel it out and divide both sides by 25.

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5000000=50e^{0.0277t}\\\frac{5000000}{50} =e^{0.0277t}\\100000=e^{0.0277t}\\ln100000=lne^{0.0277t}\\ln100000=0.02777t(lne)\\\frac{ln100000}{0.0277} =t

t=415.63 minutes

6 0
3 years ago
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