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cestrela7 [59]
3 years ago
6

Help please!!!!!!!!!!!!​

Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

  \log_{9}{\dfrac{13}{x}}=\log_{9}{\boxed{13}}-\log_{9}{x}

Step-by-step explanation:

The rule is ...

  log(a/b) = log(a) -log(b) . . . . all logs to the same base

Then for a/b = 13/x, this becomes ...

  log(13/x) = log(13) -log(x)

If the base of logarithms is 9, then this is ...

  log9(13/x) = log9(13) -log9(x)

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kap26 [50]
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3 years ago
Karen already owns 3 hair bands, and additional hair bands are priced at 8 for a dollar. How much money does Karen need to spend
kiruha [24]

Answer:

Karen needs to spend $4.5 to buy new hair bands.

Step-by-step explanation:

Given:

Hair bands Karen have = 3

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Total Hair bands she require = 39

Hence Number of of new hair bands require = Total Hair bands she require - Hair bands Karen have = 39 -3 = 36

we need to find how much money she need to spend to buy new hair bands.

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By using Unitary method we get;

Money spend on new hair bands = \frac{36}{8} = \$4.5

Hence,Karen needs to spend $4.5 to buy new hair bands.

8 0
3 years ago
Jane has a checkbook balance of $68.00. She then writes two checks, one for $5.00 and one for $62.50. She also deposits $75.00.
nataly862011 [7]
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8 0
3 years ago
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pashok25 [27]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Simplify the expression<br><br>cot^2x - cot^2x cos^2x
andrew-mc [135]
Cot^2x - cot^2x cos^2x
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= (cos^2x/sin^2x) { sin^2x }
= cos^2x
8 0
3 years ago
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