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cestrela7 [59]
3 years ago
6

Help please!!!!!!!!!!!!​

Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

  \log_{9}{\dfrac{13}{x}}=\log_{9}{\boxed{13}}-\log_{9}{x}

Step-by-step explanation:

The rule is ...

  log(a/b) = log(a) -log(b) . . . . all logs to the same base

Then for a/b = 13/x, this becomes ...

  log(13/x) = log(13) -log(x)

If the base of logarithms is 9, then this is ...

  log9(13/x) = log9(13) -log9(x)

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5 x 5 x 6 = 150

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25 x 6 = 150

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