Help please!!!!!!!!!!!!

Mathematics

1 answer:

Vladimir79 [104]2 years ago

4 0

Answer:

$\log_{9}{\dfrac{13}{x}}=\log_{9}{\boxed{13}}-\log_{9}{x}$

Step-by-step explanation:

The rule is ...

log(a/b) = log(a) -log(b) . . . . all logs to the same base

Then for a/b = 13/x, this becomes ...

log(13/x) = log(13) -log(x)

If the base of logarithms is 9, then this is ...

log9(13/x) = log9(13) -log9(x)

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