Find the slope of line that passes through (5,6) and (7,9)
1 answer:
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Answer:
- g(5x) = 0
- x = -10
Step-by-step explanation:
Do what your instructions say: read the graph and solve.
1. In order to find x, you look for the point where g(x) is 4. That point is found where x = -2. (See the first attachment.)
Then 5x = 5·(-2) = -10. To answer the question, you need to find the value of g(-10). Look where the graph crosses the vertical line at x=-10. It is at y=0, so ...
... g(5x) = g(-10) = 0
2. You already found the answer to this when looking for the answer to the first question. g(x) = 0 when x = -10. (See the second attachment.)
Answer:
b. x² + 8x + 12 =
1. use the factoring X (see attachment)
2. 6 x 2 = 12; 6 + 2 = 12
3. (x + 6)(x + 2) = 0
4. x = -6, -2
c. x² + 13x + 12 =
1. 12 x 1 = 12; 12 + 1 = 13
2. (x + 12)(x + 1) = 0
3. x = -12, -1
c. x² + x - 12 =
1. 4 · (-3) = -12; 4 - 3 = 1
2. (x +4)(x - 3) = 0
3. x = -4, 3
f. x² + 15x + 36 =
1. 12 x 3 = 36; 12 + 3 = 15
2. (x + 12)(x + 3) = 0
3. x = -12, -3
hope this helps :)
