=
1/3 ( because the limit as x approaches 0 of t/sin t = 1 ).
Answer:
20
Step-by-step explanation:
For the sake of the problem, let's make female workers "x" and male workers "y".
x+y<40 This equation shows that the total number of workers has a max of 40.
30x+20y<1,000 This equation shows that the total cost the manager pays ($30 to each woman, $20 to each man) has a max of $1,000.
Now you can solve for x and y.
X+y<40
-y -y
X<-y+40
Substitute -y+40 in for X in the second equation
30(-y+40)+20y<1,000
-30y+1200+20y<1,000 Distribute
-10y+1,200<1,000 Combine like terms
-10y<-200 Subtract 1,200
y>20 Divide by -10; flip the sign
Since y>20, and y=male workers, you now know that the minimum
number of male workers he should send is 20
Answer:
11
Step-by-step explanation:
<u><em>SUBTRACT</em></u>
Answer:
If the equation is 3x^2+6y^2, when x=0 and y=2.
Then, 3(0)^2+6(2)^2=
So, 0+6(4)= 24
Therefore, the answer is 24.
Step-by-step explanation:
