All categories

3 years ago

Solve 2 log x = log 36

Mathematics

2 answers:

zheka24 [161]3 years ago

8 0

2log x= log 36
$logx^{2} =log 36$
$x^{2} =36$
x=6

kirill [66]3 years ago

3 0

Answer:

x=6

Step-by-step explanation:

You might be interested in

A. in terms of the number of marked elk, what is the relative frequency of male elk, female elk, adult elk, and baby elk? write

mash [69]

The relative frequency of the marked elks are:

Male Elk = 7/30
Female Elk = 4/15
Adult Elk= 173/450
Baby Elk = 26/22

<h3>How to determine the relative frequency?</h3>

From the complete question, we have:

Male = 105
Female = 120
Adult = 173
Baby = 52
Total = 450

The relative frequency of each is then calculated as:

Male Elk = 105/450

Male Elk = 7/30

Female Elk = 120/450

Female Elk = 4/15

Adult Elk= 173/450

Baby Elk = 52/450

Baby Elk = 26/22

<h3>The number of Elks in the park</h3>

Using the data in (a), we can conclude that:

There are 105 male, 120 female, 173 adult, and 26 baby in the park

Read more about frequency table at:

brainly.com/question/1094036

#SPJ1

4 0

1 year ago

Determine which equation has exactly one real solution. PLS HELPP

sergey [27]

Answer:

b) $4x^2-12x+9=0$

Step-by-step explanation:

We can use the discriminant $b^2-4ac$ to determine how many real solutions a quadratic equation in the form $ax^2+bx+c=0$ has.

discriminant > 0 ⇒ 2 real solutions
discriminant = 0 ⇒ 1 real solution
discriminant < 0 ⇒ no real solutions

$5x^2+9x-4=0$

$b^2-4ac=9^2-4(5)(-4)=161 > 0\implies \textsf{2 solutions}$

$4x^2-12x+9=0$

$b^2-4ac=(-12)^2-4(4)(9)=0 \implies \textsf{1 solution}$

$-9x^2+6x+1=0$

$b^2-4ac=6^2-4(-9)(1)=72 > 0 \implies \textsf{2 solutions}$

$-2x^2-7=0$

$b^2-4ac=0^2-4(-2)(-7)=-56 < 0 \implies \textsf{no solutions}$

4 0

1 year ago

The globe used in social studies class has a diameter of 42 centimeters, What is its volume

Leni [432]

Answer:

Step-by-step explanation: pi r^2

so 42/2 equals 21 radius

volume=22/7 x 21^2

v=1385

5 0

2 years ago

Read 2 more answers

A ball is thrown into the air. The height in feet of the ball can be modeled by the equation h = -16t2 + 20t + 6 where t is the

makkiz [27]

$f(t)=h=-16t^2+20t+6

$

a=-16, b=20, c =6

Δ= $b^2-4ac=20^2-4*(-16)*6=400+384=784$

$\sqrt{Δ}=\sqrt{784}=28$

max:

$p=-\frac{b}{2a}=-\frac{20}{-32}=\frac{20}{32}=\frac{5}{8}$

max heigh: $h=-16(\frac{5}{8})^2+20*\frac{5}{8}+6=-16\frac{25}{64}+\frac{100}{8}+6$

$h=-\frac{25}{4}+\frac{50}{4}+6=\frac{-25+50+24}{4}=\frac{49}{4}$

$h=\frac{49}{4}$ at $t=\frac{5}{8}s$

will fall down at t:

$t=\frac{-20-28}{-32}=\frac{-48}{-32}=\frac{3}{2}=1.5$

$t=1.5s$

8 0

2 years ago

Find the mean, the median, and all modes for the data in the given frequency distribution. (Round your answers to one decimal pl

kvasek [131]

Answer: Mean = 7.8

Median = 9

Mode = 2,9

Step-by-step explanation: <u>Mean</u> is the average value of a data set. Mean from a frequency table is calculated as:

$E(X)=\frac{2(10)+3(9)+9(10)+11(7)+12(3)+15(4)+16(3)}{10+9+10+7+3+4+3}$

E(X) = 7.8

Mean for the given frequency distribtuion is 7.8.

<u>Median</u> is the central term of a set of numbers. Median in a frequency table is calculated as:

1) Find total number, n:

n = 10 + 9 + 10 + 7 + 3 + 4 + 3 = 46

2) Find position, using: $\frac{n+1}{2}$

$\frac{n+1}{2}=\frac{47}{2}$ = 23.5

Median is in the 23.5th position.

3) Find the position by adding frequencies: for this frequency distribution, 23.5th position is 9

Median for this frequency distribution is 9.

<u>Mode</u> is the number or value associated with the highest frequency.

In this frequency distribution, 2 and 9 points happen 10 times. So, mode is 2 and 9.

Mode for this distribution is 2 and 9.

7 0

2 years ago