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Elena L [17]
3 years ago
10

Solve 2 log x = log 36

Mathematics
2 answers:
zheka24 [161]3 years ago
8 0
2log x= log 36
logx^{2} =log 36
x^{2} =36
x=6
kirill [66]3 years ago
3 0

Answer:

x=6

Step-by-step explanation:

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Please help me with #'s 5&6
Fynjy0 [20]

5.\\(x+3)^2+7=-2\qquad|-7\\\\(x+3)^2=-9 < 0\\\\\text{NO REAL SOLUTION}\\\\(x+3)^2=-9\to x+3=\pm\sqrt{-9}\\\\x+3=-3i\ \vee\ x+3=3i\qquad|-3\\\\\boxed{x=-3-3i\ \vee\ x=-3+3i}

6.\\4(x-10)^2=25\qquad|:4\\\\(x-10)^2=\dfrac{25}{4}\to x-10=\pm\sqrt{\dfrac{25}{4}}\\\\x-10=-\dfrac{\sqrt{25}}{\sqrt4}\ \vee\ x-10=\dfrac{\sqrt{25}}{\sqrt4}\\\\x-10=-\dfrac{5}{2}\ \vee\ x-10=\dfrac{5}{2}\\\\x-10=-2.5\ \vee\ x-10=2.5\qquad|+10\\\\\boxed{x=7.5\ \vee\ x=12.5}

7 0
3 years ago
Cans of corn are on sale at 10 for $4. Find the cost of 15 cans?
SpyIntel [72]
10/15 = 4/x
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8 0
3 years ago
In Exercise,find the horizontal asymptote of the graph of the function.<br> f(x) = 8x^3+2/2x^3+x
KIM [24]

Answer:

Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at  y=4

Step-by-step explanation:

I attached the graph of the function.

Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0

When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2))  y=\frac{8}{2}=4

6 0
3 years ago
What is the factorization of x^3 + 8?
Genrish500 [490]
X^3 + 8 = 
<span>factorized 
( x + 2 )</span><span>( <span><span>x2− 2x </span>+ 4 </span><span>)
</span></span>
8 0
3 years ago
Graph the system of equations on graph paper to answer the question. Y=2/5x+4 and y=2x+12 what is the solution for this system o
riadik2000 [5.3K]

Answer:

Solution of the given equations is (-5,2)

Step-by-step explanation:

We have been given the following system of equations:

y = (2/5)x + 4

y = 2x + 12

The solution of the system of equation can be found by finding the point of intersection of both lines on the graph. The graph of both equations is attached below.

As we can see that both the lines intersect each other at one point, and that point is (-5,2). So the solution of the given equations is (-5,2)

6 0
2 years ago
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