Question

The sum of two integers is 33. The larger is 6 more than twice the smaller. Find the two

Answer 1

Answer:

24 and 9

Step-by-step explanation:

Hi there!

Let x be equal to the larger integer.

Let y be equal to the smaller integer.

1) Construct equations

1. $x+y=33$ (The sum of two integers is 33)
2. $x=6+2y$ (The larger is 6 more than twice the smaller)

2) Solve for one of the integer

Isolate x in the first equation

$x+y=33\\x=33-y$

Plug the first equation into the second

$33-y=6+2y$

Combine like terms

$33-6=2y+y\\27=3y\\9=y$

Therefore, the smaller integer is 9.

3) Solve for the other integer

$x+y=33$

Plug in y (9)

$x+9=33\\x=33-9\\x=24$

Therefore, the larger integer is 24.

I hope this helps!

Answer 2

First we called x is the smaller number
next we have larger number is 2x+6
=>we have:2x+6+x=33
<=>x=9
so we have the larger number is 33-9=24