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3 years ago

Multiply the polynomial 10. (3-2v)(2-5v) 11. (5x-4)(3x2+x-5)

Mathematics

1 answer:

tino4ka555 [31]3 years ago

5 0

Answer:

10) $10v^2-19v+6$

11) $15x^3-7x^2-29x+20$

Step-by-step explanation:

Well first let's make the box.

10)

Look at the image below ↓

$10v^2-19v+6$

11)

Look at the image below ↓

$15x^3-7x^2-29x+20$

Thus,

number 10 is $10v^2-19v+6$ and number 11 is $15x^3-7x^2-29x+20$ .

Hope this helps :)

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3 years ago

Find the perimeter of the following triangle.

pashok25 [27]

Hello!

To find the perimeter of the triangle, we need to find the length of all the sides using the distance formula.

The distance formula is: $d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

First, we can find the distance between the points (-3, -1) and (2, -1). The point (-3, -1) can be assigned to $(x_{1},y_{1})$ , and (2, -1) is assigned to $(x_{2},y_{2})$ . Then, substitute the values into the formula.

$d =\sqrt{(2 - (-3))^{2}+ (-1 - (-1))^{2}}$

$d =\sqrt{5^{2}+0^{2}}$

$d =\sqrt{25} = 5$

The distance between the points (-3, -1) and (2, -1) is 5 units.

Secondly, we need to find the distance between the points (2, 3) and (2, -1). Assign those points to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then substitute it into the formula.

$d =\sqrt{(2 - 2)^{2}+ (-1 - 3)^{2}}$

$d =\sqrt{0^{2}+(-4)^{2}}$

$d =\sqrt{16} = 4$

The distance between the two points (2, 3) and (2, -1) is 4 units.

Finally, we use the distance formula again to find the distance between the points (-3, -1) and (2, 3). Remember the assign the ordered pairs to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ and substitute!

$d =\sqrt{(2 -(-3))^{2}+ (3 - (-1))^{2}}$