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2 years ago

What is the y-value of point A?

Mathematics

2 answers:

PSYCHO15rus [73]2 years ago

6 0

Answer: 1

The full term is (6,1)

Kobotan [32]2 years ago

3 0

Answer:

Step-by-step explanation:

Trust me on this, also can I have brainiest please?

Hope you do well! :D

You might be interested in

The shortest side of an isosceles triangle is 2x - 3 inches long. the longer sides are 6 inches longer than the shortest side. t

Zolol [24]

Side 1 = short side = 2x-3
side 2 = longer side = (short side) + 6 = (2x-3)+6 = 2x+3
side 3 = side 2 = 2x+3

Side 2 and side 3 are the longer two congruent sides

Add up the three sides and set them equal to the given perimeter of 33. Solve for x

(side1)+(side2)+(side3) = perimeter
(2x-3)+(2x+3)+(2x+3) = 33
(2x+2x+2x) + (-3+3+3) = 33
6x+3 = 33
6x+3-3 = 33-3
6x = 30
6x/6 = 30/6
x = 5

If x = 5, then the longer sides are 2*x+3 = 2*5+3 = 10+3 = 13 inches each
(note: the short side is 2*x-3=2*5-3=10-3 = 7 inches)

Answer: 13 inches

8 0

3 years ago

To find the surface area of the pyramid, in square inches, Vikram wrote (33.2) (34.2) + 4 (one-half (34.2) (28.4)). What error d

madam [21]

Answer:

B. He used the wrong expression to represent the area of the base of the pyramid.

Step-by-step explanation:

Given

See attachment for pyramid

$Area = (33.2)(34.2) + 4 * \frac{1}{2} * 34.4 * 28.4$

Required

Vikram's error

The surface area of a square pyramid is:

$Area = Base\ Area + 4 * Area \triangle$

Where

$Base\ Area = Length * Length$

$Base\ Area = 34.2 * 34.2$

$4 * Area \triangle = 4 * \frac{1}{2} * Base * Height$

$4 * Area \triangle = 4 * \frac{1}{2} * 34.2 * 28.4$

So:

$Area = Base\ Area + 4 * Area \triangle$

$Area = 34.2 * 34.2 + 4 * \frac{1}{2} * 34.2 * 28.4$

By comparing the calculated expression with

$Area = (33.2)(34.2) + 4 * \frac{1}{2} * 34.4 * 28.4$

Option (b) is correct

3 0

2 years ago

If a•b=b, what must the value of a be?

Mila [183]

Answer: I think f

Step-by-step explanation:

8 0

2 years ago

Pls solve part b) iii thanks

Viktor [21]

The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

Base of the tree, b = 50 meters

Angle (x) = 32 degrees

Calculate the height (h) of the tree using:

tan(x) = height/base

So, we have:

tan(32°) = h/50

Make h the subject

h= 50 × tan(32°)

Evaluate

h = 31.24

Hence, the height of the tree is 31.24 meters

<h3>How to determine the distance between Q and the base of the tree?</h3>

The distance (d) between Q and the base of the tree

This is calculated using the following Pythagoras theorem

d = √(100² + 50²)

Evaluate

d = 111.80

Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

tan(x) = h/d

This gives

tan(x) = 31.24/111.80

Evaluate the quotient

tan(x) = 0.2794

Take the arc tan of both sides

x = 15.61

<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees