A photographer’s camera sits on a tripod that is 1.8 m above the ground. The base of the tripod is 44 m from the base of a tree.
The photographer spots a woodpecker in the tree at a 39° angle of elevation.
To the nearest tenth of a meter, how high above the ground is the woodpecker?
To the nearest tenth of a meter, how high above the ground is the woodpecker?
1 answer:
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Answer:
48 cats
Step-by-step explanation:
Am interesting factoid about ratios:
The ratio can be separated into fractional parts of
and
. We need to know the cat part.
, so that is the fraction part. Then, we multiply this fraction by 168 to get the total number of cats. This number is 48.
Answer:
3
Step-by-step explanation:
Intercept theorem
DE // CB ⇒
⇒
⇒ ? = 3
