A photographer’s camera sits on a tripod that is 1.8 m above the ground. The base of the tripod is 44 m from the base of a tree.
The photographer spots a woodpecker in the tree at a 39° angle of elevation.
To the nearest tenth of a meter, how high above the ground is the woodpecker?
To the nearest tenth of a meter, how high above the ground is the woodpecker?
1 answer:
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Answer:
Horizontal Asymptote: y=2
Vertical Asymptote: x=3
Step-by-step explanation:
One way: Look at graph
Look at for a horizontal or vertical line that both lines don't touch.
Second Way:
When you look for vertical asymptotes, you set the denominator equal to zero and solve.
For example, the second question has a denominator of x-3.
x-3=0
x=3 (This is the vertical asymptote)
When you look for horizontal asymptote, you do long division.
For example, the first question
The answer will be 2. 2 is the quotient. You only want quotient not remainder.
y=2.