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xenn [34]
2 years ago
10

I need help with number20.

Mathematics
2 answers:
labwork [276]2 years ago
6 0
So if there’s 64 tables and you want them to be arranged in a square then 8 tables would be in each row! I got that because the square root of 64 is 8. Another way to think of it is 8^2 = 64
natulia [17]2 years ago
3 0
The manager arranges the tables in rows of 8. because a a square on the multiplication chart is always going to be the square root and the square root of 64 is 8.
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What is the value of x?<br> 12 units<br> 15 units<br> 20 units<br> 25 units
Firlakuza [10]

Answer:

The answer is 12 units.

Step-by-step explanation:

Looking at the figure we see that

(1).9^2+x^2=SR^2

(2).16^2+x^2=RQ^2 and

(3).SR^2+RQ^2=(9+16)^2

Now from equations (1) and (2) we have values for SR^2 and RQ^2, so we put those into the equation (3) and get:

9^2+x^2+16^2+x^2=(9+16)^2

\rightarrow 337+2x^2=625

\boxed{\therefore x= 12.}

Therefore the answer is 12 units.

6 0
2 years ago
Read 2 more answers
The length of a rectangle is 3 inches more than twice its width, and its area is 65 square inches. What is the width?
tino4ka555 [31]

That makes no sense, what DO you get?

The correct answer is, A, or question 1, or 2w + 3.

Go ahead and click that like button and why don't you rate 5 stars as well!:)

My profile name is SweetyPie12, why don't you hit that friend request button!:)

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lol ;)

7 0
3 years ago
Whats the solution ​
Sergio039 [100]

Answer:

Step-by-step explanation:

To find the center and the radius, we need to put the equation in the (x-a)^2+(y-b)^2=r^2 [a is the x-coordinate, b is the y-coordinate, and r is the radius].

(x+6)^2+(y+7)^2 - 36 - 49 + 69 = 0

(x+6)^2+(y+7)^2 - 16 = 0

(x+6)^2+(y+7)^2 = 16

(x+6)^2+(y+7)^2 = 4^2

The center is (-6,-7) and the radius is 4.

Hope this helps!

5 0
2 years ago
Could someone please help me out? I've tried to solve this but I'm really having some trouble with it. Please try to explain it
guajiro [1.7K]

To find the area of the shaded region you need find the area of the shaded region and subtract the area of the unshaded region.

Area of a rectangle = width x length

A = (x + 10) x (2x + 5)

Next apply FOIL or First Outer Inner Last

A = (x * 2x) (x * 5) (10 * 2x) (10 * 5)

A= 2x2 + 5x + 20x + 50

A= 2x2 +25x +50

 

Area of a square=  sides2

A= (x + 1)2

A= (x+1) (x+1)

Next apply FOIL or First Outer Inner Last

A = (x *x) (1*x) (1*x) (1*1)

A = x2 + 1x + 1x +1

A= x2 + 2x +1

 

A= 2x2 +25x +50 - 2x2 +25x +50

A= 50x + 100





4 0
3 years ago
Its just a line ;)<br> ___________________
Andrei [34K]

Answer:

I need points

Step-by-step explanation:

hhhccchhxjcjc

4 0
3 years ago
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