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loris [4]
2 years ago
5

Help me with this pls

Mathematics
2 answers:
EastWind [94]2 years ago
8 0

Answer:

the diameter is 6 units

Step-by-step explanation:

3×2=6

alukav5142 [94]2 years ago
8 0
The diameter would be 6 I think
You might be interested in
Exercise
svp [43]

By addition of all the exercise and substracting it from 1 hourJavier runs on treadmill on Monday is 0.40 hour.

Now According to the question javier completed 3 repetitions of each exercise so by multiplication time taken by javier to complete each exercise is as follow;

Squats = 0.8*3= 0.24 hour

Crunches = 0.03*3 = 0.09 hour

Lunges = 0.04*3 = 0.12 hour

curls = 0.05*3 = 0.15 hour

we can calculate total time taken to complete all exercise by Addition is,

0.24 + 0.09 + 0.12 + 0.15

0.60 hour

time taken on treadmill by javier;

1 hour - 0.60 hour

0.40 hour

Read more about Addition here:

brainly.com/question/20658817

#SPJ4

4 0
1 year ago
100 points gor correct answer Identify the base of a triangle in which h=(3x+15) ft and A=(15x+75) ft^2.
ivolga24 [154]

Answer:

b = 10

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the height )

Here h = 3x + 15 and A = 15x + 75, thus

\frac{1}{2} × b × (3x + 15) = 15x + 75

Multiply both sides by 2 to clear the fraction

b(3x + 15) = 30x + 150

Divide both sides by (3x + 15)

b = \frac{30x+150}{3x+15} ← factor numerator and denominator

  = \frac{30(x + 5)}{3(x+5)} ← cancel the factor (x + 5) on numerator/denominator

  = \frac{30}{3}

  = 10

7 0
3 years ago
Read 2 more answers
Evaluate 9 ÷ 3[(18 − 10) − 22].
dlinn [17]

Answer:

-42

Step-by-step explanation:

3 0
3 years ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
2 years ago
Read 2 more answers
Can someone help me please!!
hodyreva [135]

Answer:

  1. idk

Step-by-step explanation:

i just need points :/ v

8 0
3 years ago
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