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3 years ago

12

A man worked 48 hours in one week. His regular pay was $7.80 per hour with time and a half of overtime.find his gross earnings f

or a week

1 answer:

Svetradugi [14.3K]3 years ago

7 0

Answer:

I have no idea sorry

Step-by-step explanation:

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。find the solution of the system of equations shown on the graph.<br> enter the correct answer

DochEvi [55]

The solution would be the exact point where the lines meet which is at (-4,3)

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2 years ago

PLEASE HELP! In a film study, a sample of 300 movies was found to have an average runtime of 116 minutes with a standard deviati

BigorU [14]

Answer:

The answer is 1.42!!!!!!

Step-by-step explanation:

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2 years ago

Use this idea to find the value of x in the diagram at<br> right. Be sure to show all work.<br> 71°

EleoNora [17]

We have that the value of x in the diagram at the right is

x=109

From the question we are told

Use this idea to find the value of x in the diagram at right.

From The diagram we have a Triangle with its base angles equal

Generally the equation for the Triangle is mathematically given as

180=2b+y

Where

b=Base angles

Since Angle on a straight line is 90

Therefore

180=71+x

x=109

In conclusion

The value of x in the diagram at the right is

x=109

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2 years ago

If you have $100 and then lose $25 what is the percent change

katovenus [111]

$\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}$

The lost percentage is 25%

The percentage remaining is 75%

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2 years ago

Simplify the rational expression. State any restrictions on the variable.

ExtremeBDS [4]

we are given

$\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}$

Firstly, we will factor numerators and denominators

$\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-6)(n^2-4)}{(n^2-3)(n^2-6)}$

we can see that

n^2 -6 is factor on both numerator and denominator

so, it will get cancelled

and n^2 -6 can not be equal to 0

so, one of restriction is

$n^2-6\neq 0$

$n\neq -+ \sqrt{6}$

we can simplify it

$\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-4)}{(n^2-3)}$

we know that denominator can not be zero

$n^2-3\neq 0$

$n\neq -+ \sqrt{3}$

so, option-B.......Answer

3 0

3 years ago