De Answer is:
1:2 2:4 3:6 4:8 5:10 8:10 10:20
Step-by-step explanation:
multiply paper by 2 to get cards
![\bf \begin{array}{clclll} -6&+&6\sqrt{3}\ i\\ \uparrow &&\uparrow \\ a&&b \end{array}\qquad \begin{cases} r=\sqrt{a^2+b^2}\\ \theta =tan^{-1}\left( \frac{b}{a} \right) \end{cases}\qquad r[cos(\theta )+i\ sin(\theta )]\\\\ -------------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bclclll%7D%0A-6%26%2B%266%5Csqrt%7B3%7D%5C%20i%5C%5C%0A%5Cuparrow%20%26%26%5Cuparrow%20%5C%5C%0Aa%26%26b%0A%5Cend%7Barray%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ar%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%5C%5C%0A%5Ctheta%20%3Dtan%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7Bb%7D%7Ba%7D%20%5Cright%29%0A%5Cend%7Bcases%7D%5Cqquad%20r%5Bcos%28%5Ctheta%20%29%2Bi%5C%20sin%28%5Ctheta%20%29%5D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C)
now, notice, there are two valid angles for such a tangent, however, if we look at the complex pair, the "a" is negative and the "b" is positive, that means, "x" is negative and "y" is positive, and that only occurs in the 2nd quadrant, so the angle is in the second quadrant, not on the fourth quadrant.
thus
![\bf 12\left[cos\left( \frac{2\pi }{3} \right) +i\ sin\left( \frac{2\pi }{3} \right) \right]](https://tex.z-dn.net/?f=%5Cbf%2012%5Cleft%5Bcos%5Cleft%28%20%5Cfrac%7B2%5Cpi%20%7D%7B3%7D%20%5Cright%29%20%2Bi%5C%20sin%5Cleft%28%20%5Cfrac%7B2%5Cpi%20%7D%7B3%7D%20%5Cright%29%20%5Cright%5D)
Molly's equation
15x + 10 = 100
-10 -10
15x=90
/15 /15
x=6
Maddie's equation
15x - 10 = 100
+10 +10
15x=110
/15 /15
x=7 1/3
MADDIE IS RIGHT
this is because she said 7 ans=d you cannot buy 1/3 of a shirt.
give the guy under me the 5 stare and a thanks this is his answer
If the angle G is moved to a different spot in the circle the angle FGH and angle FEH in the cyclic quadrilateral will change to make it supplementary.
<h3 /><h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is quadrilateral inscribed in a circle. It has all its vertices on the circumference of the circle.
Opposite angles in a cyclic quadrilateral are supplementary angles. That means they add up to 180 degrees.
Therefore, if he adjust point G to a different spot on the circle, angle FGH and FEH will adjust to become supplementary.
learn more on cyclic quadrilateral here: brainly.com/question/27884509
#SPJ1
<h3><u>Answer</u> :</h3>
![\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}](https://tex.z-dn.net/?f=%5Cbigstar%5C%3A%5Cboxed%7B%5Cbf%7B%5Cpurple%7Bx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%7D%3D%5Corange%7B%28%5Csqrt%5Bn%5D%7Bx%7D%29%5Em%7D%7D%7D)
Let's solve !
![:\implies\sf\:(\sqrt[2]{25})^3](https://tex.z-dn.net/?f=%3A%5Cimplies%5Csf%5C%3A%28%5Csqrt%5B2%5D%7B25%7D%29%5E3)
<u>Hence, Oprion-D is correct</u> !
