Why you would make one of the addends a tens number when solving an additional problem
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If we take the equation and multiply out the left side, we get....
+ 2xk + 
= + x +
The x^2 and k^2 cancel out on both sides leaving us with this...
2kx = x
If we divide both sides by 2x to isolate k, k ends up = 1/2
The x^2 and k^2 cancel out on both sides leaving us with this...
2kx = x
If we divide both sides by 2x to isolate k, k ends up = 1/2