Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height
b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²
Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²
data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft
(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.
Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³
Answer: ≈202.3 ft³
(16+5)4÷2=42
21×4÷2=42
84÷2=42
42=42
that is were to but you answer
Answer:
Step-by-step explanation:
You have a 30-60-90 triangle. The sides of a 30-60-90 are in the ratio 1:√3:2.
The side opposite the 30° angle is 5, so the side opposite the 60° angle is 5√3, and the side opposite the 90° angle is 5×2 = 10.
x = 5√3
y = 10
