Question

The coefficient of static friction between a block and a horizontal floor is 0.4500, while the coefficient of kinetic friction is 0.1500. The mass of the block is 4.400 kg. If a horizontal force is slowly increased until it is barely enough to make the block start moving, what is the net force on the block the instant that it starts to slide?

Answer 1

Answer:

The net force on the block is 19.40 N.

Explanation:

Given that,

Coefficient of static friction = 0.4500

Coefficient of kinetic friction = 0.1500

Mass of block = 4.400 kg

We need to calculate the net force required to make the block slide

$F=\mu_{s} mg$

Put the value into the formula

$F=0.4500\times4.400\times9.8$

$F=19.40\ N$

Hence, The net force on the block is 19.40 N.