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Molodets [167]
2 years ago
8

Example of first, second and third law of motion.​

Physics
1 answer:
statuscvo [17]2 years ago
4 0

Examples of Newton's three law of motion.

First law of motion: A rocket being launched up in the atmosphere.

Second law of motion:while riding a bicycle, a bicycle acts as a mass and our legs pushing on the pedals of the bicycle is the force.

Third law of motion:when we jump off from the boat,the boat moves backward.

Hope,it will helpyouu!

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Extra credit calculate the total mechanical energy of a pendulum as it swings from its highest point to its lowest point
Korolek [52]
Is there any numbers to your question?
Keep in mind, the energy is conserved in a pendulum.
Here’s more information:
https://blogs.bu.edu/ggarber/interlace/pendulum/energy-in-a-pendulum/
4 0
3 years ago
A dog runs with an initial velocity of 7.5 m/s on a waxed floor. It slides to a stop in 15 seconds. What is the acceleration?
Leni [432]

Answer:

-0.5 m/s^2

Explanation:

Acceleration = change in velocity / total time

7.5 / 15 = 0.5

3 0
2 years ago
How many values must a 1-D<br> motion problem give you in<br> order to solve it?
MrRa [10]

Answer:

I think it is B: 3

Explanation:

3 0
3 years ago
he fan blades on a jet engine make one thousand revolutions in a time of 54.9 ms. What is the angular frequency of the blades?
Gnesinka [82]

So, the angular frequency of the blades approximately <u>36.43π rad/s</u>.

<h3>Introduction</h3>

Hi ! Here I will discuss about the angular frequency or what is also often called the angular velocity because it has the same unit dimensions. <u>Angular frequency occurs, when an object vibrates (either moving harmoniously / oscillating or moving in a circle)</u>. Angular frequency can be roughly interpreted as the magnitude of the change in angle (in units of rad) per unit time. So, based on this understanding, the angular frequency can be calculated using the equation :

\boxed{\sf{\bold{\omega = \frac{\theta}{t}}}}

With the following condition :

  • \sf{\omega} = angular frequency (rad/s)
  • \sf{\theta} = change of angle value (rad)
  • t = interval of the time (s)

<h3>Problem Solving</h3>

We know that :

  • \sf{\theta} = change of angle value = 1,000 revolution = 1,000 × 2π rad = 2,000π rad/s >> Remember 1 rev = 2π rad/s.
  • t = interval of the time = 54.9 s.

What was asked :

  • \sf{\omega} = angular frequency = ... rad/s

Step by step :

\sf{\omega = \frac{\theta}{t}}

\sf{\omega = \frac{2,000 \pi}{54.9}}

\boxed{\sf{\omega \approx 36.43 \pi \: rad/s}}

<h3>Conclusion :</h3>

So, the angular frequency of the blades approximately 36.43π rad/s.

8 0
2 years ago
What does that make?
Kobotan [32]

Answer:

lithium

Explanation:

A lithium atom contains 3 protons in its nucleus irrespective of the number of neutrons or electrons. Notice that because the lithium atom always has 3 protons, the atomic number for lithium is always 3. The mass number, however, is 6 in the isotope with 3 neutrons, and 7 in the isotope with 4 neutrons.

7 0
3 years ago
Read 2 more answers
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