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makkiz [27]
3 years ago
8

What cannot be used to dry utensils?​

Physics
1 answer:
Mashcka [7]3 years ago
3 0

Answer:

Wiping cloth

Explanation:

When the wiping cloth is used to “clean” another surface, it will contaminate it with the bacteria. To avoid bacterial growth on the wiping cloth, a wet wiping cloth must be stored in a proper sanitizing solution between uses. Provide Proper Concentration of. Sanitizing Solution for Wiping Cloths.

wiping cloth cannot be used on a surface where raw meat was cleaned, utensils, plates and other kitchen eating accessories because of it's ability to contact germs and bacteria.

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Two parallel plates have an area of
Murrr4er [49]

Answer:

8.85

Explanation:

The computation of the charge that must place on them in order to create 1000 N/C field between the plates is shown below:

We know that

E = (Q/A) ÷ E_o

1000 = Q ÷ 0.01×8.85× 10^-12

Q = 8.85 × 10^-12

So,

The answer is 8.85

The above formula should be applied so that the correct value could come

And, the same would be relevant

3 0
3 years ago
What is measurement ?​
bazaltina [42]

Answer:

Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events

7 0
3 years ago
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Lindsay climbs a ladder with power output R. Brian climbs the same ladder in the same amount of time with
Aleksandr [31]

Answer:

I believe it's c if not then B

7 0
3 years ago
Low beam headlamps are only effective for speeds up to __________ mph.
Romashka-Z-Leto [24]
th answer is 20-25mph
8 0
3 years ago
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A reactor operating at 1 MW is scrammed by instantaneous insertion of $5.00 of negative reactivity. Approximately how long does
Novosadov [1.4K]

Answer:

time is 3333.33 min or 55.55 hr

Explanation:

given data

reactor operating = 1 MW

negative reactivity =  $5

power = 1 miliwatt

to find out

how long does it take

solution

we know here power coefficient that is

power coefficient = \frac{10^{6} }{10^{6} }

power coefficient = 1

so time required to reach power is

power =  reactivity × time / power coefficient + reactor operating

1 × 10^{-3} = -5 t / 1  +  1 × 10^{6}

5t =  10^{6} - 10^{-3}

t = 199999.99 sec

so time is 3333.33 min or 55.55 hr

4 0
4 years ago
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