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EastWind [94]
3 years ago
8

A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4       ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28   momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

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