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3 years ago

A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The

Physics

1 answer:

tensa zangetsu [6.8K]3 years ago

5 0

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4 ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28 momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

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When one form of energy is converted into another what is the name of that

Svetradugi [14.3K]

Transformation of energy, because energy cannot be created or destroyed

8 0

3 years ago

A heat pump absorbs heat from the atmosphere at a rate of 30 kW. If work is being done to run this heat pump at a rate of 7.7 kW

Volgvan

Answer:

Option D 3.9

Explanation:

First, you need to use the correct equation which is the following:

COP = Q/W

Where:

Q = heat absorbed

W = work done by the pump

COP = coefficient of perfomance

We have all the data, so, all you need to do is replace in the above expression and you shoould get the correct result:

COP = 30 / 7.7

COP = 3.896

This result you can round it to 3.9. option D.

8 0

3 years ago

Resistance to the motion of an automobile consists of road friction, which is almost independent of speed, and air drag, which i

Troyanec [42]

Answer:

73.52983 Hp

Explanation:

m = Mass of car = $\dfrac{W}{g}$

W = Weight of car = 12000 N

a = Acceleration = 0.96 m/s²

Velocity of the car

$v=82\times \dfrac{1000}{3600}\\\Rightarrow v=\dfrac{82}{3.6}\\\Rightarrow v=\dfrac{41}{1.8}$

From the question

$F=300+1.8v^2\\\Rightarrow F=300+1.8\times \left(\dfrac{41}{1.8}\right)^2\\\Rightarrow F=1233.88\ N$

Balancing the forces

$\dfrac{P}{v}-1233.88=ma\\\Rightarrow P=(ma+12000)v\\\Rightarrow P=\left(\dfrac{12000}{9.81}\times 0.96+1233.88\right)\dfrac{41}{1.8}\\\Rightarrow P=54853.26055\ W=\dfrac{54853.26055}{746}\\\Rightarrow P=73.52983\ Hp$

The power is 73.52983 Hp

6 0

3 years ago

4500 miles to inches

Volgvan

Answer:

2.8512*10^8 inches

Explanation:

Seeing as the ratio for miles to inches is 1 mile = 63360 inches, set up an equation. 1 mile / 63360 inches = 4500 miles / x inches. Cross multiply and simplify to 2.8512*10^8 inches. Hope this helps! :)

6 0

3 years ago

HELP + extra pts // Two 10-m high diving platforms are at opposing ends of a 30-m pool. How fast must two clowns run straight of

ZanzabumX [31]

Explanation:

The clowns need to leave the diving boards with enough horizontal velocity such that each travels 15 m (half the width of the pool) in the same time that they fall (vertically) the 10-m from the top of the diving board.

We'll assume no force acts on the clowns horizontally to slow them down while they are in flight. And we'll assume that only gravity acts on the clowns vertically.

We can treat the horizontal and vertical components separately. This will help simplify the problem.

Let's start with the vertical displacement. Let's say the clown is dropped from a height of 10-m. How long would it take them to fall that distance?

Using our equations of motion (with constant, linear acceleration), we can solve for this time. $d = vt + \frac{1}{2} at^2$

Where d is the distance travelled, v is the initial velocity, a is acceleration, and t is time.

If the clown is dropped, they have an initial velocity of 0 (zero). We assumed only gravity acts on the clown, so acceleration equals the gravitational acceleration on earth. $a = 9.8m/s^2$

The distance the clown travels is 10-m from the diving board to the surface of the water.

Let's solve. $10 = 0*t + \frac{1}{2} (9.8) t^2 \rightarrow 20/9.8 = t^2 \rightarrow t = \sqrt{20/9.8}$

Now that we know time, we can calculate how fast the clown needs to be running when they leap from the diving board to cover a distance of 15-m (Remember, half the width of the pool.)

Using our equations of motion, we know that $d = vt + 0.5at^2$

We assumed no forces act horizontally on the clown, therefore a = 0. We just need to solve for v. Substituting in the time we just solved for, we get something like this. $15 = v \sqrt{20/9.8}$

I'll leave it to you to solve this equation.

6 0

3 years ago