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Lorico [155]
3 years ago
13

Can someone help me with this?

Mathematics
1 answer:
charle [14.2K]3 years ago
7 0

Answer:

abbfbfv  gb fg

Step-by-step explanation:

fv bfxc bxfv

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Simplify the square root of 32/5
elixir [45]
Remember \sqrt{ \frac{x}{y} } = \frac{ \sqrt{x} }{ \sqrt{y} }
and
\sqrt{ab^2} =b \sqrt{a}
\sqrt{ \frac{32}{5} } = \frac{ \sqrt{(4^2)(2)} }{ \sqrt{5} } = \frac{ 4\sqrt{2} }{ \sqrt{5} }
times whoe thing by \frac{ \sqrt{5} }{ \sqrt{5} }
\frac{4 \sqrt{10} }{5}


3 0
3 years ago
If Jerry has four apples and you take away two how many does Jerry have
Effectus [21]

Answer:

Jerry will have two apples only

4-2=2

7 0
4 years ago
Read 2 more answers
A certain piece of copper wire is determined
Sati [7]

Answer:

14

Step-by-step explanation:

mass of 100 centimeters of copper wire is 2.00

so, mass of 1 centimeter of copper wire will be \frac{2}{100}

hence, 14 centimeters of copper wire will provide .28 copper

8 0
3 years ago
4(x-2)=2(x+7) helpp pleasee
Talja [164]

4x-8=2x+14

subtract 2x on both sides and add 8 on both sides so x=11

7 0
3 years ago
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There is a bag filled with 5 blue and 6 red marbles.
Afina-wow [57]

Answer:

The probability of getting two of the same color is 61/121 or about 50.41%.

Step-by-step explanation:

The bag is filled with five blue marbles and six red marbles.

And we want to find the probability of getting two of the same color.

If we're getting two of the same color, this means that we are either getting Red - Red or Blue - Blue.

In other words, we can find the independent probability of each case and add the probabilities together*.

The probability of getting a red marble first is:

\displaystyle P\left(\text{Red}\right)=\frac{6}{11}

Since the marble is replaced, the probability of getting another red is: \displaystyle P\left(\text{Red, Red}\right)=\frac{6}{11}\cdot \frac{6}{11}=\frac{36}{121}

The probability of getting a blue marble first is:

\displaystyle P\left(\text{Blue}\right)=\frac{5}{11}

And the probability of getting another blue is:

\displaystyle P\left(\text{Blue, Blue}\right)=\frac{5}{11}\cdot \frac{5}{11}=\frac{25}{121}

So, the probability of getting two of the same color is:

\displaystyle P(\text{Same})=\frac{36}{121}+\frac{25}{121}=\frac{61}{121}\approx50.41\%

*Note:

We can only add the probabilities together because the event is mutually exclusive. That is, a red marble is a red marble and a blue marble is a blue marble: a marble cannot be both red and blue simultaneously.

4 0
3 years ago
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