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yawa3891 [41]
3 years ago
10

Substances that are more dense have ___________ (lower or higher) specific gravity.

Chemistry
1 answer:
natita [175]3 years ago
4 0

Answer:

Higher

Explanation:

The answer is higher because Specific gravity is the density of a substance divided by the density of water.  Specific gravity is almost always very close to the same value as the density is, meaning the higher, or more dense, a substance is, the higher the specific gravity is.

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The crush is thicker in the ocean
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Explain why kerosene is used to remove stains from clothes ​
yarga [219]

Answer:

White spirits (used in lighter fluid), turpentine and Kerosene can cope with fat/oil stains, tar/asphalt and some adhesives. Many pre-wash spot treatments contain solvents. Mild Acids - such as white vinegar, cream of tartar or lemon juice help remove rust and some food stains.

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5 0
4 years ago
What type of bond is expected between two carbon atoms?
tatuchka [14]
<h3>Answer:</h3><h2>Covalent Bonds</h2>

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Explanation:

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3 0
3 years ago
A student dissolves of styrene in of a solvent with a density of . The student notices that the volume of the solvent does not c
raketka [301]

Answer:

0.576M and 0.655m

Explanation:

<em>...Dissolves 15.0g of styrene (C₈H₈) in 250.mL of a solvent with a density of 0.88g/mL...</em>

<em />

Molarity is defined as moles of solute (Styrene in this case) per liter of solution whereas molality is the moles of solute per kg of solvent. Thus, we need to find the moles of styrene, the volume in liters of the solution and the mass in kg of the solvent as follows:

<em>Moles styrene:</em>

Molar mass C₈H₈:

8C = 12.01g/mol*8 = 96.08g/mol

8H = 1.005g/mol* 8 = 8.04g/mol

96.08g/mol + 8.04g/mol = 104.12g/mol

Moles of 15.0g of styrene are:

15.0g * (1mol / 104.12g) = 0.144 moles of styrene

<em>Liters solution:</em>

250mL * (1L / 1000mL) = 0.250L

<em>kg solvent:</em>

250mL * (0.88g/mL) * (1kg / 1000g) = 0.220kg

Molarity is:

0.144 moles / 0.250L =

<h3>0.576M</h3>

Molality is:

0.144 moles / 0.220kg =

<h3>0.655m</h3>
8 0
3 years ago
What is the volume at STP of 3.44 x 1023 molecules of CO2
almond37 [142]

Answer:

C. 12.8 liters.

Explanation:

The Standard Temperature and Pressure (STP) of a gas are 273.15 K and 100 kilopascals. From Avogadro's Law, a mole of carbon dioxide contains 6.022 \times 10^{23} molecules. If we suppose that carbon dioxide behaves ideally, then the equation of state for ideal gas is:

P\cdot V = n\cdot R_{u}\cdot T (1)

P\cdot V = \frac{r\cdot R_{u}\cdot T}{N_{A}} (1b)

Where:

P - Pressure, measured in pascals.

V - Volume, measured in liters.

r - Amount of molecules, no unit.

N_{A} - Avogadro's number, no unit.

R_{u} - Ideal gas constant, measured in pascal-liters per mole-Kelvin.

T - Temperature, measured in Kelvin.

If we know that P = 100000\,Pa, r = 3.44\times 10^{23}, N_{A} = 6.022\times 10^{23}, T = 273.15\,K and R_{u} = 8.314\times 10^{3}\,\frac{L\cdot Pa}{mol\cdot K}, then the volume of carbon dioxide at STP is:

V = \frac{r\cdot R_{u}\cdot T}{N_{A}\cdot P}

V = \frac{(3.44\times 10^{23})\cdot \left(8.314\times 10^{3}\,\frac{L\cdot Pa}{mol\cdot K} \right)\cdot (273.15\,K)}{(6.022\times 10^{23})\cdot (100000\,Pa)}

V = 12.972\,L

Therefore, the correct answer is C.

8 0
3 years ago
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